of course ...


(actually I did that correctly in my original file, but the char conversion
error occured at  int main(int argc, char* argv[]){ int i; char b[4096]; ...
if(b[i]!=argv[1]) ...
                ^
I seem not to have watched the compiler output concentratedly enough)


thanks!


"Walter" <walter@digitalmars.com> schrieb im Newsbeitrag news:b2orci$23m4$3@digitaldaemon.com...
> Replace:
>     FILE f;
> with:
>     FILE *f;

Lars Hansen schrieb...
>  int main(int argc, char* argv[]){ int i; char b[4096]; ...
> if(b[i]!=argv[1]) ...
     ^^^^  ^^^^^^^
       |      +----- type char*
       +-----------  type char

You try to compare a char with a char* which is type incompatible. BTW, be carefull when comparing pointers. In the above case a string compare would be better:

   if(strcmp(a, argv[1])==0) ...

> I seem not to have watched the compiler output concentratedly enough)
Compiler messages are somtimes confusing :-)

- Heinz