Thank you very much!

that cleared a problem I had for me!

(tj, sometimes (when not using it for a long time) it's directly in front of
you and you don't recognize it (I didn't get the code to work as expected
actually): I need to dereference argv[1]! of course...)

Lars


"Heinz Saathoff" <hsaat@bre.ipnet.de> schrieb im Newsbeitrag news:MPG.18bab22821d8c3d69896b5@news.digitalmars.com...
> Lars Hansen schrieb...
> >  int main(int argc, char* argv[]){ int i; char b[4096]; ...
> > if(b[i]!=argv[1]) ...
>      ^^^^  ^^^^^^^
>        |      +----- type char*
>        +-----------  type char
>
> You try to compare a char with a char* which is type incompatible. BTW, be carefull when comparing pointers. In the above case a string compare would be better:
>
>    if(strcmp(a, argv[1])==0) ...
>
> > I seem not to have watched the compiler output concentratedly enough)
> Compiler messages are somtimes confusing :-)
>
> - Heinz
>