How do I convert this C declaration to D:

union FloatIEEE754
{
    float floatValue;
    struct
    {
        unsigned int mantissa : 23;
        unsigned int exponent : 8;
        unsigned int sign : 1;
    } mpn;
};



-- 
Julio César Carrascal Urquijo
http://jcesar.f2o.org/
-----BEGIN GEEK CODE BLOCK-----
Version: 3.12
GCS$ d- s+:+ a-- C++> ULS++ P++ L+> !E W+++ N+ o? K? w++>
O---@ M V? PS+ PE Y+ PGP t+ 5- X+++@ R- tv+(++) b++> DI!
D++> G e+> h-- r- y+
------END GEEK CODE BLOCK------

In article <c9q9ns$14mm$1@digitaldaemon.com>, =?ISO-8859-1?Q?Julio_C=E9sar_Carrascal_Urquijo?= says...
>
>How do I convert this C declaration to D:
>
>union FloatIEEE754
>{
>     float floatValue;
>     struct
>     {
>         unsigned int mantissa : 23;
>         unsigned int exponent : 8;
>         unsigned int sign : 1;
>     } mpn;
>};

Maybe like this:

struct FloatIEEE754 {

float floatValue;

int as_uint()
{
return * cast(uint*) (& floatValue);
}

uint sign()
{
return as_uint >>> 31;
}
uint exponent()
{
return as_uint << 1 >> 24;
}
uint mantissa()
{
return as_uint << 9 >>> 9;
}
}

This will allow:

struct FloatIEEE754 x;
x.floatValue = 1.123;

int a = x.sign;
int b = x.exponent;
int c = x.mantissa;

I don't remember how C++ bitfields or IEEE floats are packed, so you may need to reverse the shifts.

Kevin