std.string.split and std.string.splitlines don't seem to be stopping at the delimiters for substrings.

Here's an example:
char[] str1 = "A B C D";
char[][] str2 = split(str1);

Will result with str2 equal to:
"A B C D"
"B C D"
"C D"
"D"

mcl wrote:
> std.string.split and std.string.splitlines don't seem to be stopping at the
> delimiters for substrings.  
> 
> Here's an example:
> char[] str1 = "A B C D";
> char[][] str2 = split(str1);
> 
> Will result with str2 equal to:
> "A B C D"
> "B C D"
> "C D"
> "D"

This is probably because you're using printf instead of writef. :)

str2's elements point inside str1, but never modifies them, so there is only ever one terminating null.

 -- andy

It works for me. Maybe there is something else wrong in your code. Post the entire (but as small as possible) example that has this behaviour.

"mcl" <mcl_member@pathlink.com> wrote in message news:chgvft$116p$1@digitaldaemon.com...
> std.string.split and std.string.splitlines don't seem to be stopping at
the
> delimiters for substrings.
>
> Here's an example:
> char[] str1 = "A B C D";
> char[][] str2 = split(str1);
>
> Will result with str2 equal to:
> "A B C D"
> "B C D"
> "C D"
> "D"
>
>

In article <chh0ae$11da$1@digitaldaemon.com>, Andy Friesen says...
>This is probably because you're using printf instead of writef. :)
>
>str2's elements point inside str1, but never modifies them, so there is only ever one terminating null.
>
>  -- andy

D'oh!  I completely forgot about writef.  From now on I'm going to switch over to streams from stdio.  But first I need to get some sleep.