The following code compiles OK but behaves differently if you change the function return value from double to void:

double f(  double p ){
//void f(  double p ){
  assert( p>0.0 );
}

int main( ){
  double p = 10.01;

  f( p );

  return 0;
}

Tiago

-- 
Tiago Gasiba (M.Sc.) - http://www.gasiba.de
Everything should be made as simple as possible, but not simpler.

Tiago Gasiba wrote:
> The following code compiles OK but behaves differently if you change the function return value from double to void:
> 
> double f(  double p ){
> //void f(  double p ){
>   assert( p>0.0 );
> }
> 
> int main( ){
>   double p = 10.01;
> 
>   f( p );
> 
>   return 0;
> }
> 
> Tiago
> 

Nothing wrong here.
When the return type is not void, and your function doesn't return a value, dmd inserts an "assert(0);" at the end of the function.

zwang schrieb:

> Tiago Gasiba wrote:
>> The following code compiles OK but behaves differently if you change the function return value from double to void:
>> 
>> double f(  double p ){
>> //void f(  double p ){
>>   assert( p>0.0 );
>> }
>> 
>> int main( ){
>>   double p = 10.01;
>> 
>>   f( p );
>> 
>>   return 0;
>> }
>> 
>> Tiago
>> 
> 
> Nothing wrong here.
> When the return type is not void, and your function doesn't return a
> value, dmd inserts an "assert(0);" at the end of the function.

True. Shame on me :)
I have found a bug on assert, though, that crashes with SIGSEGV.
I'll try to reproduce it again and then post it.

Tiago

-- 
Tiago Gasiba (M.Sc.) - http://www.gasiba.de
Everything should be made as simple as possible, but not simpler.