ok, I've just unzipped dm and dmd, and I have tried to write my first
trivial D program - just to get started (below is the code I wrote). It
works, from the first try :) However, it behaves em weird.
First writefln works like it is supposed to, last one also, however writef
should just write in place haaaa and the number (hence the \r). But, when
printing in place is done, and the last writefln fires off, line where
writef wrote to disappears. How, why?

I'm on windows XP if that matters
----------------------------------------------
import std.stdio;

int main(char[][] args)
{

    writefln("===================");
    for (int i = 0; i < 50000; i++) {
      writef("haaaaa ", i, " \r");
    }
    writefln("===================");

    return 0;
}
---------------------------------------------- 

Reply to dominik,

> ok, I've just unzipped dm and dmd, and I have tried to write my first
> trivial D program - just to get started (below is the code I wrote).
> It
> works, from the first try :) However, it behaves em weird.
> First writefln works like it is supposed to, last one also, however
> writef
> should just write in place haaaa and the number (hence the \r). But,
> when
> printing in place is done, and the last writefln fires off, line where
> writef wrote to disappears. How, why?
> I'm on windows XP if that matters
> ----------------------------------------------
> import std.stdio;
> int main(char[][] args)
> {
> writefln("===================");
> for (int i = 0; i < 50000; i++) {
> writef("haaaaa ", i, " \r");
> }
> writefln("===================");
> return 0;
> }
> ----------------------------------------------

IIRC writefln starte outputting at the current location and appens a newline at the end. It does not ever add a newline at the start.

BCS wrote:
> Reply to dominik,
> 
>> ok, I've just unzipped dm and dmd, and I have tried to write my first
>> trivial D program - just to get started (below is the code I wrote).
>> It
>> works, from the first try :) However, it behaves em weird.
>> First writefln works like it is supposed to, last one also, however
>> writef
>> should just write in place haaaa and the number (hence the \r). But,
>> when
>> printing in place is done, and the last writefln fires off, line where
>> writef wrote to disappears. How, why?
>> I'm on windows XP if that matters
>> ----------------------------------------------
>> import std.stdio;
>> int main(char[][] args)
>> {
>> writefln("===================");
>> for (int i = 0; i < 50000; i++) {
>> writef("haaaaa ", i, " \r");
>> }
>> writefln("===================");
>> return 0;
>> }
>> ----------------------------------------------
> 
> IIRC writefln starte outputting at the current location and appens a newline at the end. It does not ever add a newline at the start.

The middle one is writef, not writefln.
And I think the point of this program is not to put newlines between the outputs, but to keep overwriting the last line (as a progress indicator, I guess). Which is exactly what it does on Linux by the way, with both DMD and GDC.

Well, I think on windows \r also clears the current line... So instead you should use something like:

 import std.stdio;

 int main(char[][] args)
 {

     writefln("===================");
     for (int i = 0; i < 50000; i++) {
       writef("\rhaaaaa ", i);
     }
     writefln("\n===================");

     return 0;
 }

This should work, but notice that I did not try it... dominik Wrote:

> ok, I've just unzipped dm and dmd, and I have tried to write my first
> trivial D program - just to get started (below is the code I wrote). It
> works, from the first try :) However, it behaves em weird.
> First writefln works like it is supposed to, last one also, however writef
> should just write in place haaaa and the number (hence the \r). But, when
> printing in place is done, and the last writefln fires off, line where
> writef wrote to disappears. How, why?
> 
> I'm on windows XP if that matters
> ----------------------------------------------
> import std.stdio;
> 
> int main(char[][] args)
> {
> 
>     writefln("===================");
>     for (int i = 0; i < 50000; i++) {
>       writef("haaaaa ", i, " \r");
>     }
>     writefln("===================");
> 
>     return 0;
> }
> ---------------------------------------------- 
> 
> 

Reply to Frits,

> BCS wrote:
> 
>> Reply to dominik,
>> 
>>> ----------------------------------------------
>>> import std.stdio;
>>> int main(char[][] args)
>>> {
>>> writefln("===================");
>>> for (int i = 0; i < 50000; i++) {
>>> writef("haaaaa ", i, " \r");
>>> }
>>> writefln("===================");
>>> return 0;
>>> }
>>> ----------------------------------------------
>> IIRC writefln starte outputting at the current location and appens a
>> newline at the end. It does not ever add a newline at the start.
>
> The middle one is writef, not writefln.
> And I think the point of this program is not to put newlines between
> the
> outputs, but to keep overwriting the last line (as a progress
> indicator,
> I guess). Which is exactly what it does on Linux by the way, with both
> DMD and GDC.

that is how I was reading it. The error I think is in question is that the writfln replaces the last line from the writef.

I haven't run the code so I could be totaly off base here.

"Gilles G." <schaouette@free.fr> wrote in message news:fdh95q$bir$1@digitalmars.com...
> Well, I think on windows \r also clears the current line... So instead you should use something like:

exactly, I just did that and it works. Thanks for help. I am writing tons and tons of "scripts" as command line utilites with PHP both for windows and linux every day, so I was used to the way that works there.

Thanks again guys!

BCS wrote:
> Reply to Frits,
> 
>> BCS wrote:
>>
>>> Reply to dominik,
>>>
>>>> ----------------------------------------------
>>>> import std.stdio;
>>>> int main(char[][] args)
>>>> {
>>>> writefln("===================");
>>>> for (int i = 0; i < 50000; i++) {
>>>> writef("haaaaa ", i, " \r");
>>>> }
>>>> writefln("===================");
>>>> return 0;
>>>> }
>>>> ----------------------------------------------
>>> IIRC writefln starte outputting at the current location and appens a
>>> newline at the end. It does not ever add a newline at the start.
>>
>> The middle one is writef, not writefln.
>> And I think the point of this program is not to put newlines between
>> the
>> outputs, but to keep overwriting the last line (as a progress
>> indicator,
>> I guess). Which is exactly what it does on Linux by the way, with both
>> DMD and GDC.
> 
> that is how I was reading it. The error I think is in question is that the writfln replaces the last line from the writef.

Oh wait, I must've misread the original post. Yes, that's what happens (I just didn't realize that was the problem -- I thought he didn't see the counting at all)
dominik: Try adding a writefln() right after the loop, or prepending "\n" to the last string.