With gcc, you can pass it the -static flag and it will statically link everything. Normally, with dmd (on linux at least), it dynamically links all of the C/C++ libraries that it uses. So, if I run ldd (well, ldd32 technically) on one of my programs I get:

        linux-gate.so.1 =>  (0xf7794000)
        libpthread.so.0 => /lib32/libpthread.so.0 (0xf7756000)
        libm.so.6 => /lib32/libm.so.6 (0xf7730000)
        libc.so.6 => /lib32/libc.so.6 (0xf75ea000)
        /lib32/ld-linux.so.2 (0xf7795000)

If it were gcc and -static had been used, you'd get

        not a dynamic executable

I'd like to be able to do the equivalent of -static with dmd so that my dmd- generated binaries don't have to link against any of the C/C++ libraries on my system. Is there a way to do that? I can't see any. Certainly, none of dmd's options appear to give that kind of functionality. So, if there is a way to do it, I'd like to know how. Does anyone here know how?

- Jonathan M Davis

Jonathan M Davis wrote:
> With gcc, you can pass it the -static flag and it will statically link everything. Normally, with dmd (on linux at least), it dynamically links all of the C/C++ libraries that it uses. So, if I run ldd (well, ldd32 technically) on one of my programs I get:
> 
>         linux-gate.so.1 =>  (0xf7794000)
>         libpthread.so.0 => /lib32/libpthread.so.0 (0xf7756000)
>         libm.so.6 => /lib32/libm.so.6 (0xf7730000)
>         libc.so.6 => /lib32/libc.so.6 (0xf75ea000)
>         /lib32/ld-linux.so.2 (0xf7795000)
> 
> If it were gcc and -static had been used, you'd get
> 
>         not a dynamic executable
> 
> I'd like to be able to do the equivalent of -static with dmd so that my dmd-
> generated binaries don't have to link against any of the C/C++ libraries on my system. Is there a way to do that? I can't see any. Certainly, none of dmd's options appear to give that kind of functionality. So, if there is a way to do it, I'd like to know how. Does anyone here know how?
> 
> - Jonathan M Davis

Did you try passing -L-static to DMD?

On 28/03/10 10:28, Jonathan M Davis wrote:
> With gcc, you can pass it the -static flag and it will statically link
> everything. Normally, with dmd (on linux at least), it dynamically links all
> of the C/C++ libraries that it uses. So, if I run ldd (well, ldd32
> technically) on one of my programs I get:
>
>          linux-gate.so.1 =>   (0xf7794000)
>          libpthread.so.0 =>  /lib32/libpthread.so.0 (0xf7756000)
>          libm.so.6 =>  /lib32/libm.so.6 (0xf7730000)
>          libc.so.6 =>  /lib32/libc.so.6 (0xf75ea000)
>          /lib32/ld-linux.so.2 (0xf7795000)
>
> If it were gcc and -static had been used, you'd get
>
>          not a dynamic executable
>
> I'd like to be able to do the equivalent of -static with dmd so that my dmd-
> generated binaries don't have to link against any of the C/C++ libraries on
> my system. Is there a way to do that? I can't see any. Certainly, none of
> dmd's options appear to give that kind of functionality. So, if there is a
> way to do it, I'd like to know how. Does anyone here know how?
>
> - Jonathan M Davis

I don't think dmd offers a way to do this by default, your best bet would be to add -static to the makefile and see how it goes.

On 28/03/10 12:35, Robert Clipsham wrote:
> I don't think dmd offers a way to do this by default, your best bet
> would be to add -static to the makefile and see how it goes.

I just saw Mike's reply, I notice I misread your question, sorry. I'd also try what he said, -L-static should do it.

Mike Parker wrote:

> Jonathan M Davis wrote:
>> With gcc, you can pass it the -static flag and it will statically link everything. Normally, with dmd (on linux at least), it dynamically links all of the C/C++ libraries that it uses. So, if I run ldd (well, ldd32 technically) on one of my programs I get:
>> 
>>         linux-gate.so.1 =>  (0xf7794000)
>>         libpthread.so.0 => /lib32/libpthread.so.0 (0xf7756000)
>>         libm.so.6 => /lib32/libm.so.6 (0xf7730000)
>>         libc.so.6 => /lib32/libc.so.6 (0xf75ea000)
>>         /lib32/ld-linux.so.2 (0xf7795000)
>> 
>> If it were gcc and -static had been used, you'd get
>> 
>>         not a dynamic executable
>> 
>> I'd like to be able to do the equivalent of -static with dmd so that my dmd- generated binaries don't have to link against any of the C/C++ libraries on my system. Is there a way to do that? I can't see any. Certainly, none of dmd's options appear to give that kind of functionality. So, if there is a way to do it, I'd like to know how. Does anyone here know how?
>> 
>> - Jonathan M Davis
> 
> Did you try passing -L-static to DMD?

Ah, thanks. Unfortunately, it doesn't work on my system at the moment. I get

/usr/bin/ld: cannot find -lgcc_s

However, that's probably more of an issue with my system missing stuff than there being a problem with dmd. It probably has to do with how horrid arch linux is with multilib. Still, it looks like I'm closer than I was. Thanks.

- Jonathan M Davis

Jonathan M Davis wrote:
> With gcc, you can pass it the -static flag and it will statically link everything. Normally, with dmd (on linux at least), it dynamically links all of the C/C++ libraries that it uses. So, if I run ldd (well, ldd32 technically) on one of my programs I get:
> 
>         linux-gate.so.1 =>  (0xf7794000)
>         libpthread.so.0 => /lib32/libpthread.so.0 (0xf7756000)
>         libm.so.6 => /lib32/libm.so.6 (0xf7730000)
>         libc.so.6 => /lib32/libc.so.6 (0xf75ea000)
>         /lib32/ld-linux.so.2 (0xf7795000)
> 
> If it were gcc and -static had been used, you'd get
> 
>         not a dynamic executable
> 
> I'd like to be able to do the equivalent of -static with dmd so that my dmd-
> generated binaries don't have to link against any of the C/C++ libraries on my system. Is there a way to do that? I can't see any. Certainly, none of dmd's options appear to give that kind of functionality. So, if there is a way to do it, I'd like to know how. Does anyone here know how?
> 
> - Jonathan M Davis

A friend hit the same problem recently and I was able to achieve it by performing the linking step with gcc.

1) Compile with dmd:

  dmd -c deneme.d -ofdeneme.o

2) Link with gcc:

  gcc deneme.o -static -o deneme ~/dmd/linux/lib/libphobos2.a -lpthread

Worked with my simple test application.

Ali

Ali Çehreli wrote:

> Jonathan M Davis wrote:
>> With gcc, you can pass it the -static flag and it will statically link everything. Normally, with dmd (on linux at least), it dynamically links all of the C/C++ libraries that it uses. So, if I run ldd (well, ldd32 technically) on one of my programs I get:
>> 
>>         linux-gate.so.1 =>  (0xf7794000)
>>         libpthread.so.0 => /lib32/libpthread.so.0 (0xf7756000)
>>         libm.so.6 => /lib32/libm.so.6 (0xf7730000)
>>         libc.so.6 => /lib32/libc.so.6 (0xf75ea000)
>>         /lib32/ld-linux.so.2 (0xf7795000)
>> 
>> If it were gcc and -static had been used, you'd get
>> 
>>         not a dynamic executable
>> 
>> I'd like to be able to do the equivalent of -static with dmd so that my dmd- generated binaries don't have to link against any of the C/C++ libraries on my system. Is there a way to do that? I can't see any. Certainly, none of dmd's options appear to give that kind of functionality. So, if there is a way to do it, I'd like to know how. Does anyone here know how?
>> 
>> - Jonathan M Davis
> 
> A friend hit the same problem recently and I was able to achieve it by performing the linking step with gcc.
> 
> 1) Compile with dmd:
> 
>    dmd -c deneme.d -ofdeneme.o
> 
> 2) Link with gcc:
> 
>    gcc deneme.o -static -o deneme ~/dmd/linux/lib/libphobos2.a -lpthread
> 
> Worked with my simple test application.
> 
> Ali


Thanks! That seems to have done the trick. It's a pity that it doesn't appear to be doable with dmd directly though. I should probably create an issue for it on the bug tracker.

- Jonathan M Davis

Jonathan M Davis wrote:

> Mike Parker wrote:
> 
>> Jonathan M Davis wrote:
>>> With gcc, you can pass it the -static flag and it will statically link everything. Normally, with dmd (on linux at least), it dynamically links all of the C/C++ libraries that it uses. So, if I run ldd (well, ldd32 technically) on one of my programs I get:
>>> 
>>>         linux-gate.so.1 =>  (0xf7794000)
>>>         libpthread.so.0 => /lib32/libpthread.so.0 (0xf7756000)
>>>         libm.so.6 => /lib32/libm.so.6 (0xf7730000)
>>>         libc.so.6 => /lib32/libc.so.6 (0xf75ea000)
>>>         /lib32/ld-linux.so.2 (0xf7795000)
>>> 
>>> If it were gcc and -static had been used, you'd get
>>> 
>>>         not a dynamic executable
>>> 
>>> I'd like to be able to do the equivalent of -static with dmd so that my dmd- generated binaries don't have to link against any of the C/C++ libraries on my system. Is there a way to do that? I can't see any. Certainly, none of dmd's options appear to give that kind of functionality. So, if there is a way to do it, I'd like to know how. Does anyone here know how?
>>> 
>>> - Jonathan M Davis
>> 
>> Did you try passing -L-static to DMD?
> 
> Ah, thanks. Unfortunately, it doesn't work on my system at the moment. I get
> 
> /usr/bin/ld: cannot find -lgcc_s
> 
> However, that's probably more of an issue with my system missing stuff than there being a problem with dmd. It probably has to do with how horrid arch linux is with multilib. Still, it looks like I'm closer than I was. Thanks.
> 
> - Jonathan M Davis

Well, it's not an arch linux issue. My OpenSuSE box has the same problem. It's like it's looking for gcc_s.a, but there's only a gcc_s.so. C++ programs don't have this problem, though (at least none that I've tried), so I don't know what D's doing which messes it up.

- Jonathan M Davis