Thread overview
How to create an overwriteable struct that is always const?
Jun 01, 2019
David Zhang
Jun 01, 2019
drug
Jun 01, 2019
drug
Jun 01, 2019
ag0aep6g
Jun 02, 2019
David Zhang
Jun 02, 2019
ag0aep6g
Jun 02, 2019
David Zhang
Jun 01, 2019
Jonathan M Davis
Jun 02, 2019
David Zhang
Jun 02, 2019
Jonathan M Davis
June 01, 2019
Say I have a struct `S`:

    struct S {
        /*const*/ char* pointer;
        ... other members ...

        this(/*const*/ char* p, ... others ...) {
            pointer = p;
            ...
        }
    }

What I want, is to be able to use `S` in other data structures with the following properties checked by the compiler:

 - The variable can be set
 - The variable can be read
 - The variable cannot be modified, only replaced

Is there a type-safe way to do this? If this were a class, I'd try std.typecons.Rebindable.

Thanks
June 01, 2019
01.06.2019 15:51, David Zhang пишет:
> Say I have a struct `S`:
> 
>      struct S {
>          /*const*/ char* pointer;
>          ... other members ...
> 
>          this(/*const*/ char* p, ... others ...) {
>              pointer = p;
>              ...
>          }
>      }
> 
> What I want, is to be able to use `S` in other data structures with the following properties checked by the compiler:
> 
>   - The variable can be set
>   - The variable can be read
>   - The variable cannot be modified, only replaced
> 
> Is there a type-safe way to do this? If this were a class, I'd try std.typecons.Rebindable.
> 
> Thanks

 https://dlang.org/phobos/std_typecons.html#Rebindable ?
June 01, 2019
01.06.2019 15:55, drug пишет:
>> Is there a type-safe way to do this? If this were a class, I'd try std.typecons.Rebindable.

Ah, sorry))
June 01, 2019
On 01.06.19 14:51, David Zhang wrote:
>      struct S {
>          /*const*/ char* pointer;
>          ... other members ...
> 
>          this(/*const*/ char* p, ... others ...) {
>              pointer = p;
>              ...
>          }
>      }
> 
> What I want, is to be able to use `S` in other data structures with the following properties checked by the compiler:
> 
>   - The variable can be set
>   - The variable can be read
>   - The variable cannot be modified, only replaced

How is setting/replacing different from modifying?

> Is there a type-safe way to do this? If this were a class, I'd try std.typecons.Rebindable.

struct S
{
    const(char)* pointer;
    /* ... */
}
June 01, 2019
On Saturday, June 1, 2019 6:51:08 AM MDT David Zhang via Digitalmars-d-learn wrote:
> Say I have a struct `S`:
>
>      struct S {
>          /*const*/ char* pointer;
>          ... other members ...
>
>          this(/*const*/ char* p, ... others ...) {
>              pointer = p;
>              ...
>          }
>      }
>
> What I want, is to be able to use `S` in other data structures with the following properties checked by the compiler:
>
>   - The variable can be set
>   - The variable can be read
>   - The variable cannot be modified, only replaced
>
> Is there a type-safe way to do this? If this were a class, I'd try std.typecons.Rebindable.
>
> Thanks

If any member variable of a struct is const, then you can't modify that member ever, and assignment isn't possible unless you override opAssign so that it overwrites only the mutable members. It's very rare that it makes sense to make any member variables of a struct const or immutable, because then you basically can't use assignment anymore.

You could make all of the member variables private and provide no functions that set any of them, then the only way to change any of their values would be to construct a new value of that type and assign it to the variable.

If what you really want is const(S)* though, then it would be simplest to just use const(S)*, though that requires allocating. Rebindable only exists, because the language basically conflates a reference to the class object with the class object itself, meaning that you can't make the class object const without making the reference const.

- Jonathan M Davis



June 02, 2019
On Saturday, 1 June 2019 at 13:00:50 UTC, ag0aep6g wrote:

> How is setting/replacing different from modifying?

e.g.:

    S s;

    this() { s = ...; }

    update(S s) { this.s = s; }

    mod(int i) { s.i = i; } // illegal

Kinda like how strings can be copied and assigned to, but not modified.

June 02, 2019
On Saturday, 1 June 2019 at 16:30:12 UTC, Jonathan M Davis wrote:
> If any member variable of a struct is const, then you can't modify that member ever, and assignment isn't possible unless you override opAssign so that it overwrites only the mutable members. It's very rare that it makes sense to make any member variables of a struct const or immutable, because then you basically can't use assignment anymore.
>
> You could make all of the member variables private and provide no functions that set any of them, then the only way to change any of their values would be to construct a new value of that type and assign it to the variable.
>
> - Jonathan M Davis

Ideally, I'd like for member functions to be checked against modifying s also, not just externally.
June 02, 2019
On Saturday, June 1, 2019 8:23:58 PM MDT David Zhang via Digitalmars-d-learn wrote:
> On Saturday, 1 June 2019 at 16:30:12 UTC, Jonathan M Davis wrote:
> > If any member variable of a struct is const, then you can't modify that member ever, and assignment isn't possible unless you override opAssign so that it overwrites only the mutable members. It's very rare that it makes sense to make any member variables of a struct const or immutable, because then you basically can't use assignment anymore.
> >
> > You could make all of the member variables private and provide no functions that set any of them, then the only way to change any of their values would be to construct a new value of that type and assign it to the variable.
> >
> > - Jonathan M Davis
>
> Ideally, I'd like for member functions to be checked against modifying s also, not just externally.

If the member functions are const or inout, then they won't be able to modify any members.

- Jonathan M Davis



June 02, 2019
On 02.06.19 04:22, David Zhang wrote:
> On Saturday, 1 June 2019 at 13:00:50 UTC, ag0aep6g wrote:
> 
>> How is setting/replacing different from modifying?
> 
> e.g.:
> 
>      S s;
> 
>      this() { s = ...; }
> 
>      update(S s) { this.s = s; }
> 
>      mod(int i) { s.i = i; } // illegal
> 
> Kinda like how strings can be copied and assigned to, but not modified.

The `string` itself can be modified: You can change its length, and you can make it refer to other characters. That's modifying.

You can't modify the string's characters, because the string refers to them with an `immutable(char)*` pointer. That means the pointer itself is mutable (can be modified), but the data it points to is immutable (can't be modified).

You can do the same in your struct: `const(char)* pointer;`. Then you can modify the pointer but you can't modify the data it points to.
June 02, 2019
Ah, fair enough.