so I have a main as follows

int main(string[] args)
{
    int a = 3;
    map!((int x) => x*x)((GlobalPointer!int(&a)),a);
    return 0;
}

I want to get the mangleof of the generated call to map but without referencing it in the .o and then pass the mangleof to another function. the call to map must still be instantiated.

How do I do this?

On Sunday, 24 July 2016 at 06:03:59 UTC, Nicholas Wilson wrote:
> so I have a main as follows
>
> int main(string[] args)
> {
>     int a = 3;
>     map!((int x) => x*x)((GlobalPointer!int(&a)),a);
>     return 0;
> }
>
> I want to get the mangleof of the generated call to map but without referencing it in the .o and then pass the mangleof to another function. the call to map must still be instantiated.
>
> How do I do this?

the mangled name of the call to map is

_D8dcompute5tests4test51__T3mapS40_D4main4mainFAAyaZ9__lambda2FNaNbNiNfiZiZ3mapFNaNbNiNfS8dcompute5types7pointer18__T7PointerVki1TiZ7PointeriZv

But how do I get it at compile time?

On Sunday, 24 July 2016 at 06:03:59 UTC, Nicholas Wilson wrote:
> so I have a main as follows
>
> int main(string[] args)
> {
>     int a = 3;
>     map!((int x) => x*x)((GlobalPointer!int(&a)),a);
>     return 0;
> }
>
> I want to get the mangleof of the generated call to map but without referencing it in the .o and then pass the mangleof to another function. the call to map must still be instantiated.
>
> How do I do this?

So I found std.traits.mangledName, but this still leaves a problem of that I can't get the symbol map!((int x) => x*x) without attempting to call it.