Forgive me if this has already been discussed, but how are arrays of floating point numbers compared in D? i.e. Is it a bit-by-bit comparison, is the std.math.approxEqual function get called for each element, or is it byte-by-byte across the entire array?

-Straivers

On Saturday 10 October 2015 00:14, Straivers wrote:

> Is it a bit-by-bit comparison,

no

> is the std.math.approxEqual function get called for each element,

no

> or is it byte-by-byte across the entire array?

no

After comparing the lengths, the elements are checked for equality one by one, using the usual `==` operator.

`==` is different from bitwise comparison. For example, -0f and +0f are `==` equal but have different bits, and NaNs are equal no nothing, not even themselves.

On Friday, 9 October 2015 at 22:14:09 UTC, Straivers wrote:
> Forgive me if this has already been discussed, but how are arrays of floating point numbers compared in D? i.e. Is it a bit-by-bit comparison, is the std.math.approxEqual function get called for each element, or is it byte-by-byte across the entire array?
>
> -Straivers

If you want to compare them with approxEqual, you can do:

arr1.equal!approxEqual(arr2)