void fn(scope int* var) @safe {
    (*var)++;
}

void fn2() @safe {
    int a;

    fn(&a);
}

The above program does not compile:
d.d(8): Error: cannot take address of local a in @safe function fn2

I propose that the scope keyword be activated to mean "I do not pass the pointer you gave me out of the function", which would make this code compile (as it should, as it is not doing anything unsafe).

Shachar

On Wednesday, 26 July 2017 at 08:20:42 UTC, Shachar Shemesh wrote:
> void fn(scope int* var) @safe {
>     (*var)++;
> }
>
> void fn2() @safe {
>     int a;
>
>     fn(&a);
> }
>
> The above program does not compile:
> d.d(8): Error: cannot take address of local a in @safe function fn2
>
> I propose that the scope keyword be activated to mean "I do not pass the pointer you gave me out of the function", which would make this code compile (as it should, as it is not doing anything unsafe).
>
> Shachar

compile with -dip1000