On 4 May 2012 11:46, Jonathan M Davis <jmdavisProg@gmx.com> wrote:
typeof(foo) blah2 = &func;

I just spotted the problem:
 typeof(&foo) blah = &foo;

Was missing the '&' before the type. This works... However, in my case, I don't have such a function defined to copy the type from, so it doesn't help me any :/