...alias, because the compiler doesn't see the alias after the fact, because "an alias...

...design (or implementation). People would expect an alias works the same as the original symbol...

...design (or implementation). People would expect an alias works the same as the original symbol...

...can't ever work:

```
alias identity(int i) = int;

void main() {
    alias five = identity!5...

...and it also wouldn't work with `alias five = identity!5;`. (If it wasn't...

Define "somewhere"? Because `identity` can be compiled in a different *compiler call* to `foo`. Anyways...

But if we make it work for struct, it will work with every type (with...

To explain the mechanism:

The compiler knows what the template parameters are that are used...

On 3/19/23 06:49, bomat wrote:

> I can live with the `static`
> solution...

...İşte çözümüm:

Güzel. :)

> ```d
> template whichIn(alias value, A...) {
>    alias T = typeof(value);
>    static foreach...