Hi, Walter!

Do I understand alignment settings right?
If I specify -a8, then:
    BYTE (char)         will not be aligned (it is useless)
    WORD(short int)   will be aligned on 2-byte boundary
    DWORD(long int) will be aligned on 4-byte boundary
    QWORD(double)  will be aligned on 8-byte boundary

Is that right? (double) alignment is the only difference between -a4 and -a8
, isn't it?

And what happens with alignment when parameters are placed onto stack for function call?

And, by the way, is the stack initially aligned on 16-byte boundary? Intel recommends doing so for optimal performance.

Looking forward for your answer,
        Nic Tiger.

"Nic Tiger" <nictiger@pt.comcor.ru> wrote in message news:a6hssi$13jc$1@digitaldaemon.com...
> Do I understand alignment settings right?
> If I specify -a8, then:
>     BYTE (char)         will not be aligned (it is useless)
>     WORD(short int)   will be aligned on 2-byte boundary
>     DWORD(long int) will be aligned on 4-byte boundary
>     QWORD(double)  will be aligned on 8-byte boundary
>
> Is that right? (double) alignment is the only difference between -a4
and -a8
> , isn't it?

Yes, yes.

> And what happens with alignment when parameters are placed onto stack for function call?

They are 4 byte aligned in 8.26 and earlier, 8 byte aligned for 8.27 (the beta version is available for download).


> And, by the way, is the stack initially aligned on 16-byte boundary? Intel recommends doing so for optimal performance.

Not at the moment. I should probably fix that.