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August 16, 2012
How create a operator tree?
Is there a simple function to create an operator tree of a term?

For example:
Term: 4 + 5 * 8
Tree:
[*, 5, 8, +, 4]

Or:
Term: 2 * 2 + 2:
Tree: [*, 2, 2, +, 2]
August 16, 2012
Re: How create a operator tree?
On Thursday, 16 August 2012 at 22:05:44 UTC, Namespace wrote:
> Is there a simple function to create an operator tree of a term?
>
> For example:
> Term: 4 + 5 * 8
> Tree:
> [*, 5, 8, +, 4]
>
> Or:
> Term: 2 * 2 + 2:
> Tree: [*, 2, 2, +, 2]

That seems to work: http://dpaste.dzfl.pl/95dccfa4
But it's more of a quick and dirty solution of me. Does anyone 
know, how can i do it more elegant?

P.S.: Exists such "Diff" function as i used there in the standard 
library? I think something like that would be very useful.
August 17, 2012
Re: How create a operator tree?
On 17-Aug-12 03:41, Namespace wrote:
> On Thursday, 16 August 2012 at 22:05:44 UTC, Namespace wrote:
>> Is there a simple function to create an operator tree of a term?
>>
>> For example:
>> Term: 4 + 5 * 8
>> Tree:
>> [*, 5, 8, +, 4]
>>
>> Or:
>> Term: 2 * 2 + 2:
>> Tree: [*, 2, 2, +, 2]

I do suspect you want Polish notation (and it does describe tree).
Though in this respect the above is equivalent to
+ * 2 2 2

>
> That seems to work: http://dpaste.dzfl.pl/95dccfa4
> But it's more of a quick and dirty solution of me. Does anyone know, how
> can i do it more elegant?

Wait, wait, wait.
regex is not the ultimate answer put it aside for a moment please :)

What you need is a proper operator precedence parser:
http://en.wikipedia.org/wiki/Shunting-yard_algorithm

or even simpler recursive descent parser.

>
> P.S.: Exists such "Diff" function as i used there in the standard
> library? I think something like that would be very useful.


-- 
Olshansky Dmitry
August 17, 2012
Re: How create a operator tree?
o_O
I was hoping that there is a shorter way than this.
August 17, 2012
Re: How create a operator tree?
On 17-Aug-12 12:38, Namespace wrote:
> o_O
> I was hoping that there is a shorter way than this.

In short - sure thing there is, but if you want arbitrarily deep nested 
parenthesis then no.


-- 
Olshansky Dmitry
August 17, 2012
Re: How create a operator tree?
On 08/17/2012 10:38 AM, Namespace wrote:
> o_O
> I was hoping that there is a shorter way than this.

I hacked together the following little parser (not extensively tested).

http://dpaste.dzfl.pl/e616692e

It transforms the input expression into polish notation, ignoring space
characters.
Note that it is significantly shorter than the regex attempt.

It handles numbers, unary +, -, binary +, -, *, /, ^, where ^
associates to the right, as well as nested parentheses. It should be
trivial to extend. (in this case you might want to generate the switch
cases automatically from the operator precedence table.)
August 17, 2012
Re: How create a operator tree?
On 08/17/2012 02:55 PM, Timon Gehr wrote:
> On 08/17/2012 10:38 AM, Namespace wrote:
>> o_O
>> I was hoping that there is a shorter way than this.
>
> I hacked together the following little parser (not extensively tested).
>
> http://dpaste.dzfl.pl/e616692e
>
> It transforms the input expression into polish notation, ignoring space
> characters.
> Note that it is significantly shorter than the regex attempt.
>
> It handles numbers, unary +, -, binary +, -, *, /, ^, where ^
> associates to the right, as well as nested parentheses. It should be
> trivial to extend. (in this case you might want to generate the switch
> cases automatically from the operator precedence table.)

(the first while loop is superfluous)
August 17, 2012
Re: How create a operator tree?
On Friday, 17 August 2012 at 12:55:24 UTC, Timon Gehr wrote:
> On 08/17/2012 10:38 AM, Namespace wrote:
>> o_O
>> I was hoping that there is a shorter way than this.
>
> I hacked together the following little parser (not extensively 
> tested).
>
> http://dpaste.dzfl.pl/e616692e
>
> It transforms the input expression into polish notation, 
> ignoring space
> characters.
> Note that it is significantly shorter than the regex attempt.
>
> It handles numbers, unary +, -, binary +, -, *, /, ^, where ^
> associates to the right, as well as nested parentheses. It 
> should be
> trivial to extend. (in this case you might want to generate the 
> switch
> cases automatically from the operator precedence table.)

Genial. Exactly what I'm looking for. Thanks!
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