Why it does works:

void f(out int c)
{
   if(some_cond)
	c = 10;
}

but it doesn't?

void f(out int c = 1)
{
   if(some_cond)
	c = 10;
}

it give compiler error:

Error: constant 1 is not an lvalue

My question is why it doesn't works and if there's a workaround

On Monday, 29 September 2014 at 16:09:11 UTC, AsmMan wrote:
> My question is why it doesn't works and if there's a workaround

For the same reason `ref` wouldn't work in this place: It doesn't accept rvalues.

A workaround might be to create a global variable that is initialized to the value you want, and use this as the default value. But this probably isn't what you look for, because you're most likely going to overwrite it, so the next time the function gets called, it will have a different value.

On Mon, 29 Sep 2014 16:07:49 +0000
AsmMan via Digitalmars-d-learn <digitalmars-d-learn@puremagic.com>
wrote:

> but it doesn't?
> 
> void f(out int c = 1)
'cause `out int c` is actually `int* c`. you can't assign int(1) to
pointer.

I had just forget out and ref are same as pointers... thanks guys

On Mon, 29 Sep 2014 20:22:41 +0000
AsmMan via Digitalmars-d-learn <digitalmars-d-learn@puremagic.com>
wrote:

> I had just forget out and ref are same as pointers... thanks guys
yeah, that syntactic sugar can be confusing sometimes. ;-)