The following code (line 7 and 8) causes the Error: ambiguous reference to
symbol

#include <iostream>

int main()
{
enum { zero, one, two, three };

std::cout << zero << " ";
std::cout << one << "\n";

return 0;
}

Low priority.

Steve

>#include <iostream>
>
>int main()
>{
>enum { zero, one, two, three };
>
>std::cout << zero << " ";

Here's a more isolated case:

void fn(bool i) { }
void fn(unsigned char i) { }
void fn(void (*f)()) { }

int main() {
enum { zero, one, two, three };
fn(zero);
// Error: ambiguous reference to symbol
// Had: fn(bool )
// and: fn(void (*C func)())
fn(one);
// Error: ambiguous reference to symbol
// Had: fn(bool )
// and: fn(unsigned char )
return 0;
}

both are fairly bizzarre. Clearly a problem with automatic type conversion. My guess is that it is suppossed to be the underlying type that is used for conversion. This should be an integer according to 7.2-5. sizeof "zero" is 4.

Richard