hello,

#include <stdio.h>

char *achar;
int code;

main()
{
code = 65;
sprintf(achar, "%c", code);
printf("char1=%c \n",code);  // output > char1=A
printf("char2=%s",achar);    // output > char2=(null)

}

Why char2=(null) and not A ?

"noobi" <noobi_member@pathlink.com> wrote in message news:bgdrgp$f8i$1@digitaldaemon.com...
> hello,
>
> #include <stdio.h>
>
> char *achar;
> int code;
>
> main()
> {
> code = 65;
> sprintf(achar, "%c", code);
> printf("char1=%c \n",code);  // output > char1=A
> printf("char2=%s",achar);    // output > char2=(null)
>
> }
>
> Why char2=(null) and not A ?

Because achar is statically initialized to NULL - your program never sets it to point to a buffer.

"noobi" <noobi_member@pathlink.com> wrote:

> char *achar;
> int code;
>
> main()
> {
> code = 65;
> sprintf(achar, "%c", code);

I'm amased this doesn't crash (assuming it's a 32-bit program). If it's is a 16-bit program, it shouldn't crash, but give a "NULL pointer assignment" message at program exit. Ref. Borland's c0.asm. Walter, does DMC have a similar __checknull() function?

-- 
Gisle V.

# rm /bin/laden
/bin/laden: Not found

In article <bge9fl$svp$1@digitaldaemon.com>, Walter says...
>
>
>"noobi" <noobi_member@pathlink.com> wrote in message news:bgdrgp$f8i$1@digitaldaemon.com...
>> hello,
>>
>> #include <stdio.h>
>>
>> char *achar;
>> int code;
>>
>> main()
>> {
>> code = 65;
>> sprintf(achar, "%c", code);
>> printf("char1=%c \n",code);  // output > char1=A
>> printf("char2=%s",achar);    // output > char2=(null)
>>
>> }
>>
>> Why char2=(null) and not A ?
>
>Because achar is statically initialized to NULL - your program never sets it to point to a buffer.
>
>


I need to put the Ascii character of code variable in a buffer (achar)
and display it with printf() later
How can i do it ?

"Gisle Vanem" <giva@users.sourceforge.net> wrote in message news:bgeb83$urj$1@digitaldaemon.com...
> "noobi" <noobi_member@pathlink.com> wrote:
>
> > char *achar;
> > int code;
> >
> > main()
> > {
> > code = 65;
> > sprintf(achar, "%c", code);
>
> I'm amased this doesn't crash (assuming it's a 32-bit program). If it's is a 16-bit program, it shouldn't crash, but give a "NULL pointer assignment" message at program exit. Ref. Borland's c0.asm. Walter, does DMC have a similar __checknull() function?

No, it doesn't. Sorry.

"noobi" <noobi_member@pathlink.com> wrote in message news:bgfpf7$2bh6$1@digitaldaemon.com...
> In article <bge9fl$svp$1@digitaldaemon.com>, Walter says...
> >
> >
> >"noobi" <noobi_member@pathlink.com> wrote in message news:bgdrgp$f8i$1@digitaldaemon.com...
> >> hello,
> >>
> >> #include <stdio.h>
> >>
> >> char *achar;
> >> int code;
> >>
> >> main()
> >> {
> >> code = 65;
> >> sprintf(achar, "%c", code);
> >> printf("char1=%c \n",code);  // output > char1=A
> >> printf("char2=%s",achar);    // output > char2=(null)
> >>
> >> }
> >>
> >> Why char2=(null) and not A ?
> >
> >Because achar is statically initialized to NULL - your program never sets
it
> >to point to a buffer.
> >
> >
>
>
> I need to put the Ascii character of code variable in a buffer (achar)
> and display it with printf() later
> How can i do it ?

Write:

    char achar[2];

    achar[0] = code;
    achar[1] = 0;

Hello,
I don't know which compiler you have used, however mostly standard
compilers will compile the code, but when you try to run the
object file, you can see a "Illegal address reference" kind of
error, that will abend your running process.

Here you have used a variable achar, which is "char *".
As we know that if you want to store any data in a pointer
variable we need to allocate memory for the data.
Here before allocating the memory, you are using the pointer
variable to store that "code" data.
So here sprintf should traps this out and abend the process.

As you have got the output and it is (null), this is might be,
because of the compiler.

Hope this helps.
:-)