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June 12, 2012 From number of seconds in a day to a formatted time string | ||||
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I am working with some financial data that comes in binary files. It has two fields in particular that I am trying to convert to human readable formats. The first is a date string like "20060621", which I am able to work with just fine. But then it has a field called ttim, which is the number of seconds from midnight at which a trade occurred. For example, a trade occurring at 28824 seconds in the day would have taken place at "8:00:24" (only resolution to the second). My question is: how do I convert the number of seconds (like 28824) to a formatted time string (like 08:00:24)? I looked in std.datetime, but it isn't obvious which functions I should use. You help and suggestions are much appreciated! TJB |
June 12, 2012 Re: From number of seconds in a day to a formatted time string | ||||
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Posted in reply to TJB | On Tuesday, June 12, 2012 19:28:38 TJB wrote: > I am working with some financial data that comes in binary files. It has two fields in particular that I am trying to convert to human readable formats. The first is a date string like "20060621", which I am able to work with just fine. But then it has a field called ttim, which is the number of seconds from midnight at which a trade occurred. For example, a trade occurring at 28824 seconds in the day would have taken place at "8:00:24" (only resolution to the second). > > My question is: how do I convert the number of seconds (like > 28824) to a formatted time string (like 08:00:24)? I looked in > std.datetime, but it isn't obvious which functions I should use. > > You help and suggestions are much appreciated! import std.datetime; import std.stdio; void main() { auto ttm = 28824; auto duration = dur!"seconds"(ttm); auto time = TimeOfDay.init + duration; writeln(time.toISOExtString()); } - Jonathan M Davis |
June 12, 2012 Re: From number of seconds in a day to a formatted time string | ||||
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Posted in reply to Jonathan M Davis | On Tuesday, 12 June 2012 at 17:40:40 UTC, Jonathan M Davis wrote:
> On Tuesday, June 12, 2012 19:28:38 TJB wrote:
>> I am working with some financial data that comes in binary files.
>> It has two fields in particular that I am trying to convert to
>> human readable formats. The first is a date string like
>> "20060621", which I am able to work with just fine. But then it
>> has a field called ttim, which is the number of seconds from
>> midnight at which a trade occurred. For example, a trade
>> occurring at 28824 seconds in the day would have taken place at
>> "8:00:24" (only resolution to the second).
>>
>> My question is: how do I convert the number of seconds (like
>> 28824) to a formatted time string (like 08:00:24)? I looked in
>> std.datetime, but it isn't obvious which functions I should use.
>>
>> You help and suggestions are much appreciated!
>
> import std.datetime;
> import std.stdio;
>
> void main()
> {
> auto ttm = 28824;
> auto duration = dur!"seconds"(ttm);
> auto time = TimeOfDay.init + duration;
> writeln(time.toISOExtString());
> }
>
> - Jonathan M Davis
Awesome! In the D community you get questions answered by the library writers! Thanks so much! This was perfect.
TJB
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