Let's say I want to define a mutable string:

char[] a_tmp = "abcd";  // immutable ref
char[] a;
a[] = a_tmp; // mutable copy of immutable data.

OR..?

char[] a = "abc" ~ "d";

Is there a simpler or more direct syntax?

Kevin

kevinbealer@yahoo.com wrote:
> Let's say I want to define a mutable string:
> 
> char[] a_tmp = "abcd";  // immutable ref
> char[] a;
> a[] = a_tmp; // mutable copy of immutable data.
> 
> OR..?
> 
> char[] a = "abc" ~ "d";
> 
> Is there a simpler or more direct syntax?
> 
> Kevin
> 
> 

char[] a = ("abcd").dup; may work for you.

 -- andy

kevinbealer@yahoo.com wrote:

> Let's say I want to define a mutable string:
> 
> char[] a_tmp = "abcd";  // immutable ref
> char[] a;
> a[] = a_tmp; // mutable copy of immutable data.
> 
> OR..?
> 
> char[] a = "abc" ~ "d";
> 
> Is there a simpler or more direct syntax?
> 
> Kevin

The ".dup" property will duplicate an array:
 char[] a = a_tmp.dup;

In article <c76g4e$iau$1@digitaldaemon.com>, Andy Friesen says...
>
>kevinbealer@yahoo.com wrote:
>> Let's say I want to define a mutable string:
>> 
>> char[] a_tmp = "abcd";  // immutable ref
>> char[] a;
>> a[] = a_tmp; // mutable copy of immutable data.
>> 
>> OR..?
>> 
>> char[] a = "abc" ~ "d";
>> 
>> Is there a simpler or more direct syntax?
>> 
>> Kevin
>> 
>> 
>
>char[] a = ("abcd").dup; may work for you.
>
>  -- andy

Yep, that looks like the most logical.

Kevin

On Mon, 3 May 2004 22:05:57 +0000 (UTC), kevinbealer@yahoo.com wrote:

>Let's say I want to define a mutable string:
>
>char[] a_tmp = "abcd";  // immutable ref
>char[] a;
>a[] = a_tmp; // mutable copy of immutable data.
>
>OR..?
>
>char[] a = "abc" ~ "d";
>
>Is there a simpler or more direct syntax?
>
>Kevin
>
try const .... as in
---------------------
import std.c.stdio;

void nctest() {
	char[] a = "abcd";
	char[]b = a;
 	printf( "char[] a = 'acbd'\n" );
 	printf( "char[] b = a;\n=>\n" );
	printf( "a=%.*s\n", a );
 	printf( "b=%.*s\n", b );
 	printf( "b[2]='2'...\n" );
 	b[2] = '2';
	printf( "a=%.*s\n", a );
 	printf( "b=%.*s\n", b );
}
void ctest() {
	const char[] a = "abcd";
	char[]b = a;
 	printf( "const char[] a = 'acbd'\n" );
 	printf( "char[] b = a;\n=>\n" );
 	printf( "b[2]='2'...\n" );
	printf( "a=%.*s\n", a );
 	printf( "b=%.*s\n", b );
 	printf( "b[2]='2'...\n" );
 	b[2] = '2';
	printf( "a=%.*s\n", a );
 	printf( "b=%.*s\n", b );
}

int main( char[][] args ) {
	nctest();
	ctest();
	return 0;
}
------------------------
output (as one would hope is)
char[] a = 'acbd'
char[] b = a;
=>
a=abcd
b=abcd
b[2]='2'...
a=ab2d
b=ab2d
const char[] a = 'acbd'
char[] b = a;
=>
b[2]='2'...
a=abcd
b=abcd
b[2]='2'...
a=abcd
b=ab2d