Does D's keyword "this" exactly 'behave' the same as it does in C++ (from a
programmer's and not internal perspective)? Does it always hold the address of a
class'es instance?
Rephrased: Is the statement "this()" different from statement "this"? Or is
"this" an implicit constructor call?

I'm Asking because some compiler output is confusing me.

F. Müller

F. Müller wrote:
> Rephrased: Is the statement "this()" different from statement "this"? Or is
> "this" an implicit constructor call?

They are different.  "this()" is a constructor call, and "this" is a referance to the active instance (as in C++).

> I'm Asking because some compiler output is confusing me.

What is the output?  Maybe someone here will be able to explain it for you.

-Chris S.
-Invironz

On Mon, 28 Jun 2004 06:24:54 +0000 (UTC), F. Müller <F._member@pathlink.com> wrote:

>
> Does D's keyword "this" exactly 'behave' the same as it does in C++ (from a
> programmer's and not internal perspective)? Does it always hold the address of a
> class'es instance?

Yes.

> Rephrased: Is the statement "this()" different from statement "this"?

Yes, the former is a constructor call, the latter a reference to the class.

> Or is
> "this" an implicit constructor call?

No.

> I'm Asking because some compiler output is confusing me.

Post it here. :)

Regan

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On Mon, 28 Jun 2004 03:30:48 -0500, C. Sauls <ibisbasenji@yahoo.com> wrote:
> F. Müller wrote:
>> Rephrased: Is the statement "this()" different from statement "this"? Or is
>> "this" an implicit constructor call?
>
> They are different.  "this()" is a constructor call, and "this" is a referance to the active instance (as in C++).
>
>> I'm Asking because some compiler output is confusing me.
>
> What is the output?  Maybe someone here will be able to explain it for you.

Doh! I should read em all before posting...

Regan.

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