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July 01, 2004
Bug: toStringz with 16 char strings - test.d
Linux, current compiler as of June 30. The following code:

import std.string;
void main() {
char* num = "x";
char[] testName = std.string.toString(num);
printf("%s\n", std.string.toStringz("1234567890123" ~ testName));
printf("%s\n", std.string.toStringz("12345678901234" ~ testName));
printf("%s\n", std.string.toStringz("123456789012345" ~ testName));
printf("%s\n", std.string.toStringz("1234567890123456" ~ testName));
printf("%s\n", std.string.toStringz("12345678901234567" ~ testName));
}

will output:
1234567890123x
12345678901234x
123456789012345xÿ
1234567890123456x
12345678901234567x

Notice the accented y? It shouldn't be there. This only occurs if the total
string is 16 characters long, and includes a char[].
July 01, 2004
Re: toStringz with 16 char strings - test.d
You should post this on the bugs NG

"Evil Mr Henry" <Evil_member@pathlink.com> wrote in message
news:cbvumd$2b9d$1@digitaldaemon.com...
> Linux, current compiler as of June 30. The following code:
>
> import std.string;
> void main() {
> char* num = "x";
> char[] testName = std.string.toString(num);
> printf("%s\n", std.string.toStringz("1234567890123" ~ testName));
> printf("%s\n", std.string.toStringz("12345678901234" ~ testName));
> printf("%s\n", std.string.toStringz("123456789012345" ~ testName));
> printf("%s\n", std.string.toStringz("1234567890123456" ~ testName));
> printf("%s\n", std.string.toStringz("12345678901234567" ~ testName));
> }
>
> will output:
> 1234567890123x
> 12345678901234x
> 123456789012345xÿ
> 1234567890123456x
> 12345678901234567x
>
> Notice the accented y? It shouldn't be there. This only occurs if the total
> string is 16 characters long, and includes a char[].
>
>
>
July 01, 2004
Re: toStringz with 16 char strings - test.d
I cannot reproduce this bug.

Using: DMD 0.9.4, RHEL 3.0, 2.4.21 kernel, GCC 3.2.3, can't think of
anything else important

Also tried on my WinXP system out of interest but no bug there either ;)

My output on both systems is simply:

1234567890123x
12345678901234x
123456789012345x
1234567890123456x
12345678901234567x

What Linux distro and version are you running, with what kernel, and what
version of GCC?



"Evil Mr Henry" <Evil_member@pathlink.com> wrote in message
news:cbvumd$2b9d$1@digitaldaemon.com...
> Linux, current compiler as of June 30. The following code:
>
> import std.string;
> void main() {
> char* num = "x";
> char[] testName = std.string.toString(num);
> printf("%s\n", std.string.toStringz("1234567890123" ~ testName));
> printf("%s\n", std.string.toStringz("12345678901234" ~ testName));
> printf("%s\n", std.string.toStringz("123456789012345" ~ testName));
> printf("%s\n", std.string.toStringz("1234567890123456" ~ testName));
> printf("%s\n", std.string.toStringz("12345678901234567" ~ testName));
> }
>
> will output:
> 1234567890123x
> 12345678901234x
> 123456789012345xÿ
> 1234567890123456x
> 12345678901234567x
>
> Notice the accented y? It shouldn't be there. This only occurs if the
total
> string is 16 characters long, and includes a char[].
>
>
>
July 01, 2004
Re: Bug: toStringz with 16 char strings - test.d
In article <cbvumd$2b9d$1@digitaldaemon.com>, Evil Mr Henry says...
>
>Notice the accented y? It shouldn't be there. This only occurs if the total
>string is 16 characters long, and includes a char[].

**** This bug is caused by a terminating uninitialized char ****

Report it in the bugs newsgroup, and tell them the above. Meanwhile, I suggest
you do what I did - go back to DMD 0.92.

Arcane Jill
July 01, 2004
Re: toStringz with 16 char strings - test.d
This problem was corrected in 0.94, check the date on your copy of
libphobos.a.

"Evil Mr Henry" <Evil_member@pathlink.com> wrote in message
news:cbvumd$2b9d$1@digitaldaemon.com...
> Linux, current compiler as of June 30. The following code:
>
> import std.string;
> void main() {
> char* num = "x";
> char[] testName = std.string.toString(num);
> printf("%s\n", std.string.toStringz("1234567890123" ~ testName));
> printf("%s\n", std.string.toStringz("12345678901234" ~ testName));
> printf("%s\n", std.string.toStringz("123456789012345" ~ testName));
> printf("%s\n", std.string.toStringz("1234567890123456" ~ testName));
> printf("%s\n", std.string.toStringz("12345678901234567" ~ testName));
> }
>
> will output:
> 1234567890123x
> 12345678901234x
> 123456789012345xÿ
> 1234567890123456x
> 12345678901234567x
>
> Notice the accented y? It shouldn't be there. This only occurs if the
total
> string is 16 characters long, and includes a char[].
>
>
>
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