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March 18, 2007
Re: Extended Type Design.
Andrei Alexandrescu (See Website For Email) Wrote:

> Bruno Medeiros wrote:
> > What is the status of the experimental designs for the "storage classes" 
> > manipulation that Andrei and others where thinking of for D. The last I 
> > heard from it was Andrei's max suggestion from his max design challenge, 
> > however, I think that suggestion may suffer from some problems in 
> > regards to the "maxtype" requirement, plus it is wholly incomplete in 
> > regards to how storage classes interact between each other. Like Andrei 
> > said, what is a "const inout lazy const char[]", if valid at all? Is 
> > there any news here? Is there a working(aka complete) design?
> We have talked about a design. In short, the intent is to define three 
> flavors of immutability:
> a) final - a simple storage class controlling the immutability of the 
> bits allocated for the symbol per se;
> b) const - type qualifier meaning an immutable view of an otherwise 
> modifiable data. const does not control the bits of the object, only the 
> storage addressed indirectly by it (transitively);
> c) "superconst" - denoted as "const!" or "super const": type qualifier 
> meaning that the data is genuinely unmodifiable.
> There is talk about deprecating lazy if it's best implemented via other 
> mechanisms. There is also talk about deprecating "inout" in favor of 
> "ref" on grounds that the often-useful "inout const" is likely to become 
> #1 reason for bashing D.
> To read a declaration like "const inout lazy const char[]", you can 
> first parenthesize it appropriately:
> const(inout(lazy(const(char[]))))
> The lazy thing is really a delegate that returns a const char[]. The 
> inout around it passes that delegate by reference, and the const at the 
> top makes the delegate immutable.
> Andrei

I didn't see any discussion of how a member function is to be marked as being const or non const, as in C++.

Does that mean that there are plans to make the compiler figure out which methods are const by itself ?

To do this successfully will require some way of expressing aggregation. So that the compiler can distinguish between a reference that a class may hold simply to 'look at' another class from a reference that it holds representing a 'is part of' relationship.
In C++ agregation could be expressed by simply not using a pointer, or if polymorphism or other reasons to use a pointer required, an aggregate pointer could be defined, such as :

template <typename T>
class aggregate_ptr
	T * p;

//dtors ctors etc.

   const T * operator->() const
		return p;

   T * operator->()
		return p;


Here operator -> is overloaded to so that use of this pointer as a member variable is a way of expressing aggregation. ie the pointed to class is considered part of the class the pointer is part of for const purposes.
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