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```Graham St Jack Wrote:

> On Thu, 29 Nov 2007 02:16:40 -0500, Gilles G. wrote:
>
> > there are two ways to express function
> > constness for now:
> >    const int foo();
> >    int foo() const;
> > To my mind, both solutions are unintuitive. I would expect something
> > like that:
> >    int const foo();
> > Is there any big argument against this?
>
> I agree. A definition like:
>
> const T foo();
>
> looks to me like the returned T is const, and putting the const after the function is way too non-D for me, so all that is left that makes sense is:
>
> T const foo();

I've seen Walter argue that he wants to be able to declare const functions in batch with
const{
T foo();
T bar();
}

I guess you could say that he wants const{X;} and const X; to be the same, but doesn't want const(X) and const X to be the same.  There's nothing like mixing two hotly debated threads together!  I apologize in advance for it.  I just couldn't resist since the parallels were so striking.
```
```On Tue, 04 Dec 2007 13:48:10 -0500, Jason House wrote:

> Graham St Jack Wrote:
>
>> On Thu, 29 Nov 2007 02:16:40 -0500, Gilles G. wrote:
>>
>> > there are two ways to express function constness for now:
>> >    const int foo();
>> >    int foo() const;
>> > To my mind, both solutions are unintuitive. I would expect something
>> > like that:
>> >    int const foo();
>> > Is there any big argument against this?
>>
>> I agree. A definition like:
>>
>> const T foo();
>>
>> looks to me like the returned T is const, and putting the const after the function is way too non-D for me, so all that is left that makes sense is:
>>
>> T const foo();
>
> I've seen Walter argue that he wants to be able to declare const
> functions in batch with const{
>   T foo();
>   T bar();
> }
>
> I guess you could say that he wants const{X;} and const X; to be the same, but doesn't want const(X) and const X to be the same.  There's nothing like mixing two hotly debated threads together!  I apologize in advance for it.  I just couldn't resist since the parallels were so striking.

I would have to argue that const {W;} and const X; are the same while const W* var; and const(W*) var; are different. As described in "Teach Yourself C++ in 21 Days" a block/compound statement is used to act as one statement. That is to say that only single statements are acceptable. That is to say that {W;} is in fact only X.

Now look at the second case, const must be applied to something after it, Janice assumes that it would stop at the *. However if we continue and let W* var = X then we get const(X); with the latter being const(X) var;

My question is why does const X var; have to equal const(X) var? Wouldn't it be legitimate to change ones thinking such that const X var is const(X var) even thought it is not valid syntax.

I still have a lot to learn and to apply a lot of what I know, but after reading posts and reading to understand const and its applications, I see the current syntax to work well, even though I don't think it is explained very well.
```