February 16, 2010
For some reason this creates an access violation:

	Object o;

Apparently it's by design. This expression is calling o's invariant, it does not check for null as I'd expect. But o is null so calling invariant just crashes.

According to an old bug report, things have been working like this for a long time.

It works according to spec:

I wonder how many time I wrote the above assertion thinking I was just checking for null...

Michel Fortin

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