this is going to be a bit of a nebulous question, but

if I define a template

template T(string s){
}

where s is an identifier, then is there a good way to branch T's behavior based on whether s is declared in the scope in which T gets instantiated?

Hello Ellery,

> this is going to be a bit of a nebulous question, but
> 
> if I define a template
> 
> template T(string s){
> }
> where s is an identifier, then is there a good way to branch T's
> behavior based on whether s is declared in the scope in which T gets
> instantiated?
> 

some combination of "is()" "typeof" and "mixin()" should do it.

//untested

static if( mixin("is("~s~")") ) { ... }

-- 
... <IXOYE><

On 04/01/2010 12:38 PM, BCS wrote:
> Hello Ellery,
>
>> this is going to be a bit of a nebulous question, but
>>
>> if I define a template
>>
>> template T(string s){
>> }
>> where s is an identifier, then is there a good way to branch T's
>> behavior based on whether s is declared in the scope in which T gets
>> instantiated?
>>
>
> some combination of "is()" "typeof" and "mixin()" should do it.
>
> //untested
>
> static if( mixin("is("~s~")") ) { ... }
>

All right, here's a first try:

//// test.d
module test;
import tok;

int a; //1
void main(){
    int a; //2
    void dummy(){};
    mixin T!("a");
}


//// tok.d
module tok;

int a; //3
template T(char[] k){
        static if (is(typeof(mixin(k)))){
            pragma(msg,"true");
            static if(is(typeof(mixin("."~k)))){
                pragma(msg,"uh oh");
            }
            const K = true;
        }else{
            pragma(msg,"false");
            const K = false;
        }
}


The problem I see is it can't distinguish between 1 or 2 and 3

Hello Ellery,

> The problem I see is it can't distinguish between 1 or 2 and 3
> 

OK, lets try a slightly different question:

Can code statically branch on what scope some symbol is in?

I'd look at __traits but I don't know how to do this off hand.

Being in a template mixin and getting passed in as a string just confuse the issue.

-- 
... <IXOYE><