Thread overview
why ushort alias casted to int?
Dec 22
crimaniak
Dec 22
ketmar
Dec 22
crimaniak
Dec 22
Nathan S.
December 22
My code:

alias MemSize = ushort;

struct MemRegion
{
	MemSize start;
	MemSize length;
	@property MemSize end() const { return start+length; }
}

Error: cannot implicitly convert expression `cast(int)this.start + cast(int)this.length` of type `int` to `ushort`

Both operands are the same type, so as I understand casting to longest type is not needed at all, and longest type here is ushort in any case. What am I doing wrong?
December 22
crimaniak wrote:

> Both operands are the same type, so as I understand casting to longest type is not needed at all, and longest type here is ushort in any case. What am I doing wrong?

it is hidden in specs: all types shorter than int are promoted to int before doing any math.
December 22
On Friday, 22 December 2017 at 10:18:52 UTC, ketmar wrote:
> crimaniak wrote:
>
>> Both operands are the same type, so as I understand casting to longest type is not needed at all, and longest type here is ushort in any case. What am I doing wrong?
>
> it is hidden in specs: all types shorter than int are promoted to int before doing any math.

Hm, really. ok, I will use the explicit cast, but I don't like it.
December 22
On Friday, 22 December 2017 at 10:42:28 UTC, crimaniak wrote:
> Hm, really. ok, I will use the explicit cast, but I don't like it.

It's because the C programming language has similar integer promotion rules. That doesn't make it any more convenient if you weren't expecting it but that is the reason behind it.
December 22
On Friday, 22 December 2017 at 10:14:48 UTC, crimaniak wrote:
> My code:
>
> alias MemSize = ushort;
>
> struct MemRegion
> {
> 	MemSize start;
> 	MemSize length;
> 	@property MemSize end() const { return start+length; }
> }
>
> Error: cannot implicitly convert expression `cast(int)this.start + cast(int)this.length` of type `int` to `ushort`
>
> Both operands are the same type, so as I understand casting to longest type is not needed at all, and longest type here is ushort in any case. What am I doing wrong?

@property MemSize end() const { return cast(int)(start+length); }

The rule of int promotion of smaller types comes from C as they said. There are 2 reason to do it that way. int is supposed in C to be the natural arithmetic type of the CPU it runs on, i.e. the default size the processor has the least difficulties to handle. The second reason is that it allows to detect easily without much hassle if the result of the operation is in range or not. When doing arithmetic with small integer types, it is easy that the result overflows. It is not that easy to define portably this overflow behaviour. On some cpus it would require extra instructions. D has inherited this behaviour so that copied arithmetic code coming from C behaves in the same way.

@property MemSize end() const
{
  MemSize result = start+length;
  assert(result <= MemSize.max);
  return cast(int)result;
}

with overflow arithmetic this code is not possible (as is if MemSize was uint or ulong).