Its possible to call copyctor manually without calling dtor?

ex, what i did before:

struct T{ ~this(){ writeln("DTOR"); } this(this){ writeln("POSTBLIT"); } }

T a;
T b;

memcpy(&a,&b,T.sizeof);
a.__postblit;

/*
output:
POSTBLIT
DTOR
DTOR
*/

With copy ctors, not sure what to do.


struct T{
~this(){ writeln("DTOR"); } 	
this(ref return scope T self){ writeln("COPYCTOR"); } }

T a;
T b;

memcpy(&a,&b,T.sizeof);
a.opAssign(b); //???
//same as a = b;

/*
output:
COPYCTOR
DTOR
DTOR
DTOR
*/

I want something like '.__xcopyctor'

On Saturday, 1 June 2019 at 02:27:36 UTC, SrMordred wrote:
> Its possible to call copyctor manually without calling dtor?
>
> ex, what i did before:
>
> struct T{ ~this(){ writeln("DTOR"); } this(this){ writeln("POSTBLIT"); } }
>
> T a;
> T b;
>
> memcpy(&a,&b,T.sizeof);
> a.__postblit;
>
> /*
> output:
> POSTBLIT
> DTOR
> DTOR
> */
>
> With copy ctors, not sure what to do.
>
>
> struct T{
> ~this(){ writeln("DTOR"); } 	
> this(ref return scope T self){ writeln("COPYCTOR"); } }
>
> T a;
> T b;
>
> memcpy(&a,&b,T.sizeof);
> a.opAssign(b); //???
> //same as a = b;
>
> /*
> output:
> COPYCTOR
> DTOR
> DTOR
> DTOR
> */
>
> I want something like '.__xcopyctor'

The copy constructor is implemented as an overload of `__ctor`:

import std.stdio;

struct T {
    ~this() { writeln("DTOR"); }
    this(ref return scope T self) { writeln("COPYCTOR"); }
}

void main() {
    T a;
    T b;
    a.__ctor(b);
}

/* Output:
COPYCTOR
DTOR
DTOR
*/

https://run.dlang.io/is/NeioBs

On Saturday, 1 June 2019 at 19:10:36 UTC, Paul Backus wrote:
> On Saturday, 1 June 2019 at 02:27:36 UTC, SrMordred wrote:

> void main() {
>     T a;
>     T b;
>     a.__ctor(b);
> }
> https://run.dlang.io/is/NeioBs

Thanks!
The most obvious way i didn´t think :P