If you memoize a method inside a class definition using std.functional.memoize is caching done in a per-object manner, or do all objects of this class share cached return values? Thank you.

On Friday, 19 December 2014 at 02:45:13 UTC, kyle wrote:
> If you memoize a method inside a class definition using std.functional.memoize is caching done in a per-object manner, or do all objects of this class share cached return values? Thank you.

Memoize uses one hash table per symbol it is applied to -> all objects