Hi D

I've a simple question but it's bedeviling me anyway. How do I get a string representation of the current type of a SumType? I'm trying to avoid something like this:

alias Vec3 = SumType!(void* /* invalid vector */, byte[3], short[3], char[][3]);

string prnType(Vec3 vec){

  return vec.match!(
     (void* _) => "void*",
     (byte[3] _) => "byte[3]",
     (short[3] _) => "short[3]",
     (char[][3] _) => "char[][3]"
  );
}

I'm sure there's a much easier way, especially once there's a largish number of vector types.

Thanks,

On Sunday, 1 October 2023 at 01:17:50 UTC, Chris Piker wrote:

alias Vec3 = SumType!(void* /* invalid vector */, byte[3], short[3], char[][3]);

I know it's bad form to reply to my own question, but I think I found a reasonably simple way:

string prnType(Vec3 vec){
   return vec.match!( t => typeof(t).stringof);
}

which is hardly worth making into a function of it's own. Other suggestions are welcome of course.

SumTypes are really tripping me up. Unlearning years of writing C takes more time then I'd prefer.

On Sunday, 1 October 2023 at 01:17:50 UTC, Chris Piker wrote:

alias Vec3 = SumType!(void* /* invalid vector */, byte[3], short[3], char[][3]);

string prnType(Vec3 vec){

  return vec.match!(
     (void* _) => "void*",
     (byte[3] _) => "byte[3]",
     (short[3] _) => "short[3]",
     (char[][3] _) => "char[][3]"
  );
}

return vec.match(value => typeof(value).stringof);

We posted at the same time! Thanks for help nonetheless.

I do hope over time, SumTypes get the Ali Çehreli treatment. I keep his book open on my desk all the time.