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Filter out consecutive elements based on comparison between adiacent two
Jan 31, 2019
Langer
Jan 31, 2019
Alex
Jan 31, 2019
Alex
Jan 31, 2019
Langer
January 31, 2019
Gravatar of LangerPosted by LangerReply
Langer
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Hi all,

Ditto... something like:

filter!((a,b) => a.foo != b.foo)

Thank you!
January 31, 2019
Gravatar of AlexPosted by Alex
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On Thursday, 31 January 2019 at 13:18:39 UTC, Langer wrote:
> Hi all,
>
> Ditto... something like:
>
> filter!((a,b) => a.foo != b.foo)
>
> Thank you!

I would say:

´´´
arr.group.map!(el => el[0])
´´´
January 31, 2019
Gravatar of AlexPosted by Alex
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On Thursday, 31 January 2019 at 13:18:39 UTC, Langer wrote:
> Hi all,
>
> Ditto... something like:
>
> filter!((a,b) => a.foo != b.foo)
>
> Thank you!

but... why not

´´´
arr.uniq
´´´
January 31, 2019
Gravatar of LangerPosted by Langer
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Langer
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On Thursday, 31 January 2019 at 13:25:21 UTC, Alex wrote:
> On Thursday, 31 January 2019 at 13:18:39 UTC, Langer wrote:
>> Hi all,
>>
>> Ditto... something like:
>>
>> filter!((a,b) => a.foo != b.foo)
>>
>> Thank you!
>
> but... why not
>
> ´´´
> arr.uniq
> ´´´

thank you, uniq is perfect.