Thread overview
string literal string and immutable(char)* overload ambiguity
Jul 31, 2018
Nicholas Wilson
Aug 03, 2018
Jonathan Marler
Aug 04, 2018
Jonathan Marler
July 31, 2018
is there any particular reason why

void foo(string a) {}
void foo(immutable(char)* b) {}

void bar()
{
    foo("baz");
}

result in

Error: foo called with argument types (string) matches both:
foo(string a)
and:
foo(immutable(char)* b)

especially given the pointer overload is almost always
void foo(immutable(char)* b)
{
    foo(b[0 .. strlen(b)]);
}
and if I really want to call the pointer variant I can with
    foo("baz".ptr);
but I can't call the string overload with a literal without creating a temp.

I think we should make string literals prefer string arguments.

July 31, 2018
On 7/31/18 10:13 AM, Nicholas Wilson wrote:
> is there any particular reason why
> 
> void foo(string a) {}
> void foo(immutable(char)* b) {}
> 
> void bar()
> {
>      foo("baz");
> }
> 
> result in
> 
> Error: foo called with argument types (string) matches both:
> foo(string a)
> and:
> foo(immutable(char)* b)
> 
> especially given the pointer overload is almost always
> void foo(immutable(char)* b)
> {
>      foo(b[0 .. strlen(b)]);
> }
> and if I really want to call the pointer variant I can with
>      foo("baz".ptr);
> but I can't call the string overload with a literal without creating a temp.
> 
> I think we should make string literals prefer string arguments.
> 

Absolutely, I didn't realize this was an ambiguity. It should be the same as foo(long) vs. foo(int) with foo(1).

-Steve
August 03, 2018
On Tuesday, 31 July 2018 at 15:07:04 UTC, Steven Schveighoffer wrote:
> On 7/31/18 10:13 AM, Nicholas Wilson wrote:
>> is there any particular reason why
>> 
>> void foo(string a) {}
>> void foo(immutable(char)* b) {}
>> 
>> void bar()
>> {
>>      foo("baz");
>> }
>> 
>> result in
>> 
>> Error: foo called with argument types (string) matches both:
>> foo(string a)
>> and:
>> foo(immutable(char)* b)
>> 
>> especially given the pointer overload is almost always
>> void foo(immutable(char)* b)
>> {
>>      foo(b[0 .. strlen(b)]);
>> }
>> and if I really want to call the pointer variant I can with
>>      foo("baz".ptr);
>> but I can't call the string overload with a literal without creating a temp.
>> 
>> I think we should make string literals prefer string arguments.
>> 
>
> Absolutely, I didn't realize this was an ambiguity. It should be the same as foo(long) vs. foo(int) with foo(1).
>
> -Steve

+1 for this

Although there is a solution for this today, i.e.

foo(cast(string)"baz");
foo("baz".ptr));

I see no reason why `string` shouldn't have precedence over `immutable(char)*`, especially since you can always explicitly choose the pointer variant with `.ptr.

August 04, 2018
On 8/3/18 10:26 AM, Jonathan Marler wrote:
> On Tuesday, 31 July 2018 at 15:07:04 UTC, Steven Schveighoffer wrote:
>> On 7/31/18 10:13 AM, Nicholas Wilson wrote:
>>> is there any particular reason why
>>>
>>> void foo(string a) {}
>>> void foo(immutable(char)* b) {}
>>>
>>> void bar()
>>> {
>>>      foo("baz");
>>> }
>>>
>>> result in
>>>
>>> Error: foo called with argument types (string) matches both:
>>> foo(string a)
>>> and:
>>> foo(immutable(char)* b)
>>>
>>> especially given the pointer overload is almost always
>>> void foo(immutable(char)* b)
>>> {
>>>      foo(b[0 .. strlen(b)]);
>>> }
>>> and if I really want to call the pointer variant I can with
>>>      foo("baz".ptr);
>>> but I can't call the string overload with a literal without creating a temp.
>>>
>>> I think we should make string literals prefer string arguments.
>>>
>>
>> Absolutely, I didn't realize this was an ambiguity. It should be the same as foo(long) vs. foo(int) with foo(1).
>>
> 
> +1 for this
> 
> Although there is a solution for this today, i.e.
> 
> foo(cast(string)"baz");
> foo("baz".ptr));
> 
> I see no reason why `string` shouldn't have precedence over `immutable(char)*`, especially since you can always explicitly choose the pointer variant with `.ptr.
> 
Let me rewrite your solution for int vs. long:

foo(cast(int)1);
foo(1L);

You like that too? ;)

"baz" is a string, that's its primary type. That it can be used for a const(char)* is nice for legacy C code, but shouldn't get in the way of its natural type.

-Steve
August 04, 2018
On Saturday, 4 August 2018 at 12:16:00 UTC, Steven Schveighoffer wrote:
> On 8/3/18 10:26 AM, Jonathan Marler wrote:
>> On Tuesday, 31 July 2018 at 15:07:04 UTC, Steven Schveighoffer wrote:
>>> On 7/31/18 10:13 AM, Nicholas Wilson wrote:
>>>>[...]
>>>
>>> Absolutely, I didn't realize this was an ambiguity. It should be the same as foo(long) vs. foo(int) with foo(1).
>>>
>> 
>> +1 for this
>> 
>> Although there is a solution for this today, i.e.
>> 
>> foo(cast(string)"baz");
>> foo("baz".ptr));
>> 
>> I see no reason why `string` shouldn't have precedence over `immutable(char)*`, especially since you can always explicitly choose the pointer variant with `.ptr.
>> 
> Let me rewrite your solution for int vs. long:
>
> foo(cast(int)1);
> foo(1L);
>
> You like that too? ;)
>
> "baz" is a string, that's its primary type. That it can be used for a const(char)* is nice for legacy C code, but shouldn't get in the way of its natural type.
>
> -Steve

Yeah I definitely agree.  Though there is a solution, it's ugly.  Making string have precedence over char pointers seems like only positives from what I can tell.