The following expression:

import std.math : sqrt;
sqrt(400);

produces the following compiler error:

std.math.sqrt called with argument types (int) matches both:
/usr/include/dmd/phobos/std/math.d(1592,7):     std.math.sqrt(float x)
and:
/usr/include/dmd/phobos/std/math.d(1598,6):     std.math.sqrt(real x)

Shouldn't it just pick one according to some defined rules?

On Saturday, 23 December 2017 at 07:25:34 UTC, IM wrote:
> The following expression:
>
> import std.math : sqrt;
> sqrt(400);
>
> produces the following compiler error:
>
> std.math.sqrt called with argument types (int) matches both:
> /usr/include/dmd/phobos/std/math.d(1592,7):     std.math.sqrt(float x)
> and:
> /usr/include/dmd/phobos/std/math.d(1598,6):     std.math.sqrt(real x)
>
> Shouldn't it just pick one according to some defined rules?

C++ complains the same between float and double. Just put 400.0f or whatever precision you want to use. I think it's better that it doesn't just pick one.