Excuse my ignorance, but from looking at the documentation on std.range and a quick skim of the guides mentioned there near the top, I can't see what the simple way is of creating an InputRange!(ubyte) from strings, files etc. I would have expected to find something in the DLang Tour about this, but couldn't find anything. Please can someone tell me how to do it? Just to be clear, I want to create an object which is an InputRange!(ubyte) and pass that around, rather than e.g. iterate over a string or a file.

On 09/11/2018 2:58 AM, Vinay Sajip wrote:
> Excuse my ignorance, but from looking at the documentation on std.range and a quick skim of the guides mentioned there near the top, I can't see what the simple way is of creating an InputRange!(ubyte) from strings, files etc. I would have expected to find something in the DLang Tour about this, but couldn't find anything. Please can someone tell me how to do it? Just to be clear, I want to create an object which is an InputRange!(ubyte) and pass that around, rather than e.g. iterate over a string or a file.

TLDR of how to write an input range:

struct MyInputRange {
	ubyte[] input;

	@property {
		ubyte front() {
			return this.input[0];
		}

		bool empty() {
			return this.input.length == 0;
		}
	}

	void popFront() {
		this.input = this.input[1 .. $];
	}
}

import std.stdio;

void main() {
    foreach(b; MyInputRange([1, 2, 3])) {
    	writeln(b);
    }
}

On Thursday, 8 November 2018 at 13:58:55 UTC, Vinay Sajip wrote:
> Excuse my ignorance, but from looking at the documentation on std.range and a quick skim of the guides mentioned there near the top, I can't see what the simple way is of creating an InputRange!(ubyte) from strings, files etc. I would have expected to find something in the DLang Tour about this, but couldn't find anything. Please can someone tell me how to do it? Just to be clear, I want to create an object which is an InputRange!(ubyte) and pass that around, rather than e.g. iterate over a string or a file.

You can iterate through a file one ubyte at a time using `byChunk` and `joiner`:

    auto r1 = stdin.byChunk(1024).joiner;
    assert(is(typeof(r1.front) == ubyte));

You can iterate through a string one ubyte at a time using `representation`:

    auto r2 = "To be or not to be".representation;
    assert(is(typeof(r2.front) == immutable(ubyte)));

To pass these ranges around using the `InputRange` interface, use `inputRangeObject` to wrap them:

    InputRange!ubyte r3 = inputRangeObject(r1);
    InputRange!(immutable(ubyte)) r4 = inputRangeObject(r2);

On Thursday, 8 November 2018 at 14:38:37 UTC, Paul Backus wrote:
> You can iterate through a file one ubyte at a time using `byChunk` and `joiner`:
>
>     auto r1 = stdin.byChunk(1024).joiner;
>     assert(is(typeof(r1.front) == ubyte));
>
> You can iterate through a string one ubyte at a time using `representation`:
>
>     auto r2 = "To be or not to be".representation;
>     assert(is(typeof(r2.front) == immutable(ubyte)));
>
> To pass these ranges around using the `InputRange` interface, use `inputRangeObject` to wrap them:
>
>     InputRange!ubyte r3 = inputRangeObject(r1);
>     InputRange!(immutable(ubyte)) r4 = inputRangeObject(r2);

Aha - inputRangeObject was the thing I was missing. Thanks!

On Thursday, 8 November 2018 at 14:38:37 UTC, Paul Backus wrote:
> To pass these ranges around using the `InputRange` interface, use `inputRangeObject` to wrap them:
>
>     InputRange!ubyte r3 = inputRangeObject(r1);
>     InputRange!(immutable(ubyte)) r4 = inputRangeObject(r2);

I did a bit more digging, and it seems to work for strings but not for files: The program

import std.algorithm.iteration;
import std.format;
import std.range;
import std.stdio;
import std.string;

void somefn(InputRange!(immutable(ubyte)) r) {
    writeln(format!"%s"(r));
}

void main()
{
    auto a = "Hello, world!";
    auto b = inputRangeObject(a.representation);
    somefn(b);
    auto c = stdin.byChunk(1024).joiner;
    auto d = inputRangeObject(c);
    //somefn(d);
}

compiles as given above, but if the somefn(d) line is uncommented, I get an error:

function onlineapp.somefn(InputRange!(immutable(ubyte)) r) is not callable using argument types (InputRangeObject!(Result))
onlineapp.d(18):        cannot pass argument d of type std.range.interfaces.InputRangeObject!(Result) to parameter InputRange!(immutable(ubyte)) r

Do I need to do an explicit cast? If so, can someone tell me the precise incantation? How come it doesn't figure out that the underlying range is a ubyte range, or is it to do with immutability, or something else altogether?

On Thursday, 8 November 2018 at 16:15:25 UTC, Vinay Sajip wrote:
> On Thursday, 8 November 2018 at 14:38:37 UTC, Paul Backus wrote:
>> To pass these ranges around using the `InputRange` interface, use `inputRangeObject` to wrap them:
>>
>>     InputRange!ubyte r3 = inputRangeObject(r1);
>>     InputRange!(immutable(ubyte)) r4 = inputRangeObject(r2);
>
> I did a bit more digging, and it seems to work for strings but not for files: The program
>
> import std.algorithm.iteration;
> import std.format;
> import std.range;
> import std.stdio;
> import std.string;
>
> void somefn(InputRange!(immutable(ubyte)) r) {
>     writeln(format!"%s"(r));
> }
>
> void main()
> {
>     auto a = "Hello, world!";
>     auto b = inputRangeObject(a.representation);
>     somefn(b);
>     auto c = stdin.byChunk(1024).joiner;
>     auto d = inputRangeObject(c);
>     //somefn(d);
> }
>
> compiles as given above, but if the somefn(d) line is uncommented, I get an error:
>
> function onlineapp.somefn(InputRange!(immutable(ubyte)) r) is not callable using argument types (InputRangeObject!(Result))
> onlineapp.d(18):        cannot pass argument d of type std.range.interfaces.InputRangeObject!(Result) to parameter InputRange!(immutable(ubyte)) r
>
> Do I need to do an explicit cast? If so, can someone tell me the precise incantation? How come it doesn't figure out that the underlying range is a ubyte range, or is it to do with immutability, or something else altogether?

you could use a template for somefn definition:

´´´
void somefn(T)(T r) {
    writeln(format!"%s"(r));
}
´´´

On 11/8/18 11:15 AM, Vinay Sajip wrote:
> On Thursday, 8 November 2018 at 14:38:37 UTC, Paul Backus wrote:
>> To pass these ranges around using the `InputRange` interface, use `inputRangeObject` to wrap them:
>>
>>     InputRange!ubyte r3 = inputRangeObject(r1);
>>     InputRange!(immutable(ubyte)) r4 = inputRangeObject(r2);
> 
> I did a bit more digging, and it seems to work for strings but not for files: The program
> 
> import std.algorithm.iteration;
> import std.format;
> import std.range;
> import std.stdio;
> import std.string;
> 
> void somefn(InputRange!(immutable(ubyte)) r) {
>      writeln(format!"%s"(r));
> }
> 
> void main()
> {
>      auto a = "Hello, world!";
>      auto b = inputRangeObject(a.representation);
>      somefn(b);
>      auto c = stdin.byChunk(1024).joiner;
>      auto d = inputRangeObject(c);
>      //somefn(d);
> }
> 
> compiles as given above, but if the somefn(d) line is uncommented, I get an error:
> 
> function onlineapp.somefn(InputRange!(immutable(ubyte)) r) is not callable using argument types (InputRangeObject!(Result))
> onlineapp.d(18):        cannot pass argument d of type std.range.interfaces.InputRangeObject!(Result) to parameter InputRange!(immutable(ubyte)) r
> 
> Do I need to do an explicit cast? If so, can someone tell me the precise incantation? How come it doesn't figure out that the underlying range is a ubyte range, or is it to do with immutability, or something else altogether?

A cool feature of D is to have it tell you something about your code at compile time.

I did this in a run.dlang.org playground:

pragma(msg, ElementType!(typeof(b)));
pragma(msg, ElementType!(typeof(d)));

I get:
immutable(ubyte)
ubyte

Which means they aren't the same type, and they don't define the same interface (InputRange!(ubyte) is not the same as InputRange!(immutable(ubyte)) ).

Other than simply using compile-time functions, and dropping the object interface as Alex suggests, the easiest thing I can recommend is wrapping representation into a casting input range such as map:

auto b = inputRangeObject(a.representation.map!(b => ubyte(b)));

You can see all this here:

https://run.dlang.io/is/1E6Uqj

-Steve

On Thursday, 8 November 2018 at 16:41:50 UTC, Steven Schveighoffer wrote:
> I did this in a run.dlang.org playground:
>
> pragma(msg, ElementType!(typeof(b)));
> pragma(msg, ElementType!(typeof(d)));
>
> I get:
> immutable(ubyte)
> ubyte
>
> Which means they aren't the same type, and they don't define the same interface (InputRange!(ubyte) is not the same as InputRange!(immutable(ubyte)) ).
>
> Other than simply using compile-time functions, and dropping the object interface as Alex suggests, the easiest thing I can recommend is wrapping representation into a casting input range such as map:
>
> auto b = inputRangeObject(a.representation.map!(b => ubyte(b)));
>
> You can see all this here:
>
> https://run.dlang.io/is/1E6Uqj
>
> -Steve

Thanks, guys, those are helpful pointers.