July 18, 2020 Why is typeof(readln) -> void? | ||||
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``` import std.stdio; void main() { writeln(typeof(readln()).stringof); // string writeln(typeof(readln).stringof); // void } ``` Can anybody explain the difference between readln() and readln? I read somewhere that the () were optional, so why this difference? |
July 18, 2020 Re: Why is typeof(readln) -> void? | ||||
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Posted in reply to blizzard | On 18/07/2020 9:14 PM, blizzard wrote: > Can anybody explain the difference between readln() and readln? I read somewhere that the () were optional, so why this difference? The brackets are optional when calling a function. You are not calling a function if you wrap it in typeof. "The Expression is not evaluated, it is used purely to generate the type:" https://dlang.org/spec/declaration.html#Typeof |
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