For example, something like the following:

void main() {
  char accepted_type;
  char* non_accepted_type;

  if (__traits(isPointer, typeof(accepted_type))) {
    // The type is not accepted
  }

 else { /* The type is not a pointer so its accepted */ }

  if (__traits(isPointer, typeof(non_accepted_type))) {
    // The type is not accepted
  }

 else { /* The type is not a pointer so its accepted */ }
}

In that example, the first comparison will execute the second branch and for the second comparison,
it will execute the first branch. Of course, this trait doesn't exist I used an example to show what I want
to do. Any ideas?

On Saturday, 25 June 2022 at 14:18:10 UTC, rempas wrote:

I guess you can look at the source code for

https://dlang.org/phobos/std_traits.html#isPointer

On Saturday, 25 June 2022 at 14:32:27 UTC, Ola Fosheim Grøstad wrote:

Thank you! Nice and quick ;)

For anyone interested, here's the source code:

enum bool isPointer(T) = is(T == U*, U) && __traits(isScalar, T);

Have a nice day my friend!

On Saturday, 25 June 2022 at 14:18:10 UTC, rempas wrote:

void main() {
  char accepted_type;
  char* non_accepted_type;

  if (__traits(isPointer, typeof(accepted_type))) {
    // The type is not accepted
  }

Use an is() expression:

if (is(typeof(accepted_type) == T*, T))
{
    // it's a pointer
}

In English, you read this as "if typeof(accepted_type) matches the pattern T*, where T is a type."

If you want to learn more, I recommend reading Adam Ruppe's explanation of is() expressions.

On Saturday, 25 June 2022 at 14:51:49 UTC, Paul Backus wrote:

if (is(typeof(accepted_type) == T*, T))
{
    // it's a pointer
}

Thank you too for this example! Have a nice day my friend!