I went ahead and started reading "Who's Afraid of C++?" as
suggested. Surprisingly, I also became more and more intrigued. It
was actually starting to help me better understand places where I was getting
stuck in my other studies of C.
I'm utterly *terrible* at math, but as I continued to study
all this comp. science, a light in some dark, unused part of my brain
began to slowly brighten, and I was beginning to understand!
Eureka!!
...of course, that would be the point where I crash into
some kind of math problem that completely trashed my new natural
high.
And, here it is!
Using the hexadecimal system, answer this problem:
1a + 2e =
Welp, 'Susan' said she got 48 for an answer. Well, I got
41. Not only was I waaay off, but when I saw how the answer *should* be
worked out, it knocked me into next week! (meaning it blew me
away)
...and, here's how it's worked out!
1(1 * 16) + a(10 * 1)
2(2 * 16) + e(14 * 1)
------------------
3(3 * 16) + 18(24 * 1 = 1 * 16 + 8 * 1)
"Carry the 1 from the low digit to the high digit of the
answer, to produce:
4(4 * 16) + 8(8 * 1), or 48 hex, which is the
answer"
Well, I could only figure just so many guesses as to what all
this means. But all in all, I honestly have no
clue.
All I can figure is:
* In a multi-tasked math problem, division and multiplication
are worked out before addition and subtraction.
* I'm guessing that the 4 parts to the problem represent the 4
places in a binary code that altogether make up a hexadecimal. How "way
off" am I still? Probably very...
Would anyone who is gifted (to any lengths) in the realms of
math and comp. science be willing to share in the gift and please help me
out? My math knowledge only goes as far as a small crumb of
geometry.
Thanks a Million,
Me