2013/11/20 Jakob Ovrum <jakobovrum@gmail.com>

I was not sure that the fun!int is legitimate usage.

I also ask this question. I think it may prove useful, and code in the wild might be relying on it.

One of the known issue is, that the specified type parameters may not match exactly to the function parameters position.

You can make a partially specialized lambda like follows.

X!((int a, b) => a + b)

Then, inside X(alias fun), fun!long means instantiate (int a, long b){ return a + b; }.

And of course, fun!(int, int) will be invalid.

So, specifying type parameter for the template lambda will make the template code unreliable.

I think it is not good feature in general.

Kenji Hara