On Sat, Aug 17, 2013 at 03:29:56PM -0700, Timothee Cour wrote:
[...]

> Related question:
>
> Why isn't the following allowed:
> ----
> void fun(){
> // code without version=A
>   version=A;
> // code with version=A
>   vesion(none):
> //code versioned out
> }
> ----
> I understand the grammar doesn't allow it, but what's the rationale,
> and can it be fixed?

Not exactly sure what you're trying to achieve, but isn't this what you
want:

        void fun() {
                version(A) {
                        ...
                } else {
                        ..
                }
        }

?

Or are you trying to change version=A inside the function?

T

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