Philippe,
I don't understand the example below to simulate the list comprehension syntax.  Are input1, input2 and input3 ranges?   Where is the comp function defined?
Thank you,
-clk
(Christian Keppenne)
auto lc = comp!("tuple(a,b,c)", "a*a+b*b == c*c && a<b")(input1,input2, input3);
 
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Message: 2
Date: Tue, 20 Dec 2011 21:45:26 +0100
From: Philippe Sigaud <philippe.sigaud@gmail.com>
To: "digitalmars.D.learn" <digitalmars-d-learn@puremagic.com>
Subject: Re: newbie question: Can D do this?
Message-ID:
	<CAOA6Bi6BaYm1T3PhvWY9mBRPsedK_dDjWYr-7yDO5cOV2ddiTw@mail.gmail.com>
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On Mon, Dec 19, 2011 at 17:17, clk <clk@clksoft.com> wrote:

Correct. As other have said, it's doable by combining std functions.
As fas as I know, we do not have a cartesian product range, to iterate
on all combinations of two or more ranges.

[f(x,y) for x in list1 for y in list2 if condition]

I gave it a try a few years ago and could get something like this:

auto lc = comp!("tuple(a,b,c)", "a*a+b*b == c*c && a<b")(input1,
input2, input3);

->                       mapper,         condition,
        input ranges, as many as you wish

But at the time I couldn't find a way to do bindings, that is:

[f(x,y) for x in [0..10] for y in [0..x]]
-> the range iterated by y depends on x.

If anyone has an idea, I'm game.

Philippe