On 26 November 2012 18:49, jerro <a@a.com> wrote:

How can I fix the template declaration to not error in that case?

If you want to have a template parameter that can be anything, including a a symbol or a built in type, you can use this ugly workaround:

template foo(bar...) if(bar.length == 1)
{
enum foo = 1;
}

Ahhhhh, that explains why 90% of std.traits is written in that super-weird way! I always wondered what that was all about.

When you say 'anything' though, does that include alias parameters? Will bar[0] be the equivalent of template foo(alias bar) if called with a symbol?

Ummm, immediate problem. That interferes with my argument list, inhibits consecutive parameters. You'll notice my template had 'A' on the end... it would make for a horrible API if the second arg were to come first in this case... is that the only option?