...a daemon work fast then that is ok.

This is not an either/or situation...

...but ENUM1 is constant.
                auto b = ENUM2; // OK
        }
}

void main()
{
        auto a = new shared(A...

Ok, maybe I just read more to the nuances of the summary than there actually...

...tupleof[0]; // error
    alias x = s.x; // OK
    x.writeln; // error, no instance of S...

OK, thanks. And `s.expand[0].writeln();` works too.

So the following error makes sense...

...b = ENUM2; // OK
        }
        static void g()
        {
                auto c = ENUM1; // OK
                auto d = ENUM2; // OK
        }
}

void...

...d
struct S
{
   this(int) {}
}

S s; // ok?
```

Seems like if you want to *require...

...S t = S(); // ok (constructed by calling `S.this()`)
    S u = void; // ok (not `@safe...

...T input1, ref @escapeas(input1) T input2);
```

Ok great, you modeled the escapes, congratulations.

Or...

...alias x = s.tupleof;
    x[0] = 2; // ok
    alias y = s.x;
    y = 2; // error...