Is it possible to pass a class member function as a template argument in such a way that it can 1. be called during runtime, and 2. still retrieve the UDAs of the function itself?  For example, given this setup:

struct MYUDA {}
class Foo {
	@(MYUDA) int bar(int x) { return x*2; }
}
auto foo = new Foo();

Neither of these will work:

void FCALL(alias F, V...)(V args) {
	assert(hasUDA!(F, MYUDA)); // Ok
	//assert(F(args) == 10); // Compilation Error: need `this` for `bar` of type `int(int x)`
}
FCALL!(foo.bar)(5);

void DCALL(V...)(int delegate(V) func, V args) {
	//assert(hasUDA!(func, MYUDA)); // Assertion failure (runtime delegate can't see compile-time UDAs)
	assert(func(args) == 12); // Ok
}
DCALL(&foo.bar, 6);


However, I can combine them into one function like so:

void TCALL(alias F, V...)(int delegate(V) func, V args) {
	assert(hasUDA!(F, MYUDA)); // Ok
	assert(func(args) == 14); // Ok
}
TCALL!(foo.bar)(&foo.bar, 7);

But it feels ugly having to write the same thing twice (foo.bar and &foo.bar).  I'd like to simply this somehow.  Given a template declaration like "void CALL(alias F)( ... )" is there some way to write a function parameter that takes a delegate-of-F?  Such that I can ultimate call the function as CALL(&foo.bar) and the template parameter alias is inferred.

I did figure out I can do it with mixins like so:

void MCALL(string func, V...)(V args) {
	mixin(`assert(hasUDA!(`~func~`, MYUDA));`); // Ok
	mixin(`assert(`~func~`(args) == 16);`); // Ok
}
MCALL!"foo.bar"(8);

Which works.  Is this the "best" way to do this?  Or is there another pattern that looks cleaner?

On 06/11/2018 08:46 AM, cc wrote:
> struct MYUDA {}
> class Foo {
>      @(MYUDA) int bar(int x) { return x*2; }
> }
> auto foo = new Foo();
[...]
> I did figure out I can do it with mixins like so:
> 
> void MCALL(string func, V...)(V args) {
>      mixin(`assert(hasUDA!(`~func~`, MYUDA));`); // Ok
>      mixin(`assert(`~func~`(args) == 16);`); // Ok
> }
> MCALL!"foo.bar"(8);
> 
> Which works.  Is this the "best" way to do this?

That only works when foo is visible to MCALL. That's a serious limitation.

> Or is there another pattern that looks cleaner?

I can't think of a really nice solution where you just pass `foo.bar` or `&foo.bar`. The problem is that an alias of `foo.bar` is really an alias of `Foo.bar`, i.e. there is no connection to the object `foo`. And `&foo.bar` is just a generic delegate. There is no (compile-time) type information that links it to the type `Foo`.

The best I could come up with is passing the method's name separately from the object:

----
void main()
{
    auto foo = new Foo();
    foo.nCall!"bar"(9);
}

void nCall(string methodName, O, V...)(O obj, V args)
    /* 'n' is for "name" */
{
    import std.traits: hasUDA;
    auto methodDelegate = mixin("&obj." ~ methodName);
    mixin("alias methodAlias = obj." ~ methodName ~ ";");
    assert(hasUDA!(methodAlias, MYUDA)); // Ok
    assert(methodDelegate(args) == 18); // Ok
}

struct MYUDA {}

class Foo
{
    @(MYUDA) int bar(int x) { return x*2; }
}
----

If it's feasible to hard-code a list of all possible object types into the "call" function, then you can pass `&foo.bar` and find the correct object type by trying them all:

----
void main()
{
    auto foo = new Foo();
    bCall(&foo.bar, 9);
}

void bCall(D, V...)(D methodDelegate, V args)
    /* 'b' is for "bloat" */
{
    import std.traits: hasUDA;
    import std.meta: AliasSeq;

    assert(methodDelegate(args) == 18); // Ok

    auto obj = cast(Object) methodDelegate.ptr;
    if (obj is null) return; /* Delegate is not of a method. */

    static foreach (O; AliasSeq!(Foo, /* Bar, Baz, etc */))
    {
        static foreach (mName; __traits(allMembers, O))
        {{
            alias m = AliasSeq!(__traits(getMember, O, mName))[0];
            static if (is(typeof(&m)))
            {
                if (typeid(O) == typeid(obj) &&
                    &m is cast(void*) methodDelegate.funcptr)
                {
                    assert(hasUDA!(m, MYUDA)); // Ok
                }
            }
        }}
    }
}

struct MYUDA {}

class Foo
{
    @(MYUDA) int bar(int x) { return x*2; }
}
----

But that's probably not feasible.