http://d.puremagic.com/issues/show_bug.cgi?id=10794

           Summary: Unsynchronized access to data of syncronized class
           Product: D
           Version: D2
          Platform: All
        OS/Version: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: nobody@puremagic.com
        ReportedBy: freeslave93@gmail.com


--- Comment #0 from Roman <freeslave93@gmail.com> 2013-08-11 10:11:30 PDT ---
Here is something similar to example from Alexandrescu's book (13.14.1 Temporary Protection == No Escape):

import std.stdio;

int* ptr;

void sneaky(out int bar)
{
    ptr = &bar;
}

synchronized class B
{
    private int bar;
    public void foo()
    {
        sneaky(bar);
    }
    int getBar()
    {
        return bar;
    }
    void setBar(int b)
    {
        bar = b;
    }
}

void main()
{
    auto b = new shared(B);
    b.setBar(5);
    b.foo();
    *ptr = 6;
    writeln(*ptr);
    writeln(b.getBar());
}

I just replaced 'ref' with 'out' and now it compiles fine. Is it suppose to work this way?

I also wonder why we have to write 'new shared(NameOfClass)' when class is synchronized, although we can't create not shared instance of synchronized class. Was it designed to make code more explicit?

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