July 03, 2004 I can't compile C programs w/input! | ||||
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Sorry to bother you, but whenever i try to compile a program with gets("%f", mph); or printf("%f", &kmph); in it, where im using gets() for number inputand printf for number output, the compiler gives me the error: 1 actual arguments expected for printf, had 2 so, it seems to think that me setting the function up for printing numbers is actually using 2 arguments, when it's not. If you have advice on how i can fix or prevent this from happening, please reply. Pifs_of_blu |
July 05, 2004 Re: I can't compile C programs w/input! | ||||
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Posted in reply to Pifs | Compiler may think of "printf" as taking 1 parameter only if you haven't included stdio.h and compiler autoprototyped this functions from first call, i.e: printf ( "..." ); // not knowing anything about printf, compiler may think that it accepts only one param printf ( "%d", 2 ); // certainly compiler will give error here. Make sure you #include <stdio.h> before you use printf or scanf Also, "gets" is not for formatted input, use scanf instead. But as for my feeling, I don't like scanf and never had luck to make it work. :-) Nic Tiger. "Pifs" <Pifs_member@pathlink.com> wrote in message news:cc51eq$19ic$1@digitaldaemon.com... > Sorry to bother you, but whenever i try to compile a program with > gets("%f", mph); or printf("%f", &kmph); in it, where im using gets() > for number inputand printf for number output, the compiler gives me the error: > > 1 actual arguments expected for printf, had 2 > > so, it seems to think that me setting the function up for printing numbers is > actually using 2 arguments, when it's not. If you have advice on how i can fix > or prevent this from happening, please reply. > > Pifs_of_blu |
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