May 24, 2013 deducing function/delegate in template method | ||||
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In this code:
// accepts a list of handlers, for the respective types
void addHandlers(T...)(T handlers)
{
foreach(handler; handlers)
{
addHandler(handler);
}
}
// accepts one handler, for type T
void addHandler(T)(void delegate (T) handler)
{
...
}
...
foo.addHandler((int x) { /* always deduced as delegate */ });
foo.addHandlers(delegate (int x) { /* if no scope access deduction fails */ });
If I call addHandler with a function/delegate literal then DMD deduces that the literal has to be a delegate, but if I call addHandlers then I have to explicitly mark my function/delegate literal as a delegate, otherwise the template match will fail if the function/delegate literal does not access something from its scope. Couldn't DMD also deduce this correctly in this case?
Also, how can I change addHandler to accept delegates with heterogeneous varargs? Something like:
void addHandler(T...)(void delegate (T...) handler);
so that I can do:
foo.addHandler((int x, float y) { });
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May 24, 2013 Re: deducing function/delegate in template method | ||||
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Posted in reply to Luís Marques | On Friday, 24 May 2013 at 22:37:49 UTC, Luís Marques wrote:
> foo.addHandlers(delegate (int x) { /* if no scope access deduction fails */ });
(I meant that deduction would fail if the literal was not marked as a delegate)
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