Am I missing a more agreeable way to check the return value of a C function against NULL.  It's fine if it's a char*, but if it returns a pointer to some kind of struct, one has to go through and convert each instance of NULL to a cast of the appropriate return type.  Eg cast(funnystruct*)0

  if ((tomime_fields.fld_description==cast(char*)0))
    throw new Exception("show_part_info: description is NULL");

On 1/01/2015 12:22 a.m., Laeeth Isharc wrote:
> Am I missing a more agreeable way to check the return value of a C
> function against NULL.  It's fine if it's a char*, but if it returns a
> pointer to some kind of struct, one has to go through and convert each
> instance of NULL to a cast of the appropriate return type.  Eg
> cast(funnystruct*)0
>
>    if ((tomime_fields.fld_description==cast(char*)0))
>      throw new Exception("show_part_info: description is NULL");

== for value
is for pointers

if (tomime_fields.fld_description is null)
	throw new Exception("...");

On 12/31/2014 8:29 PM, Rikki Cattermole wrote:
> On 1/01/2015 12:22 a.m., Laeeth Isharc wrote:
>> Am I missing a more agreeable way to check the return value of a C
>> function against NULL.  It's fine if it's a char*, but if it returns a
>> pointer to some kind of struct, one has to go through and convert each
>> instance of NULL to a cast of the appropriate return type.  Eg
>> cast(funnystruct*)0

You can take your pick of these:

if( !ptr ) ...
if( ptr == null ) ...
if( ptr is null ) ...


>>
>>    if ((tomime_fields.fld_description==cast(char*)0))
>>      throw new Exception("show_part_info: description is NULL");
>
> == for value
> is for pointers
>
> if (tomime_fields.fld_description is null)
>      throw new Exception("...");

Actually, while 'is' does work for pointers, it's only necessary for references.

Thanks for the help.

Laeeth