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How auto convert Variant to required function arguments?
Oct 09
Marcone
```How auto convert Variant to required function arguments?
```
```On Friday, 9 October 2020 at 00:19:20 UTC, Marcone wrote:
> How auto convert Variant to required function arguments?

import std.variant;
import std.stdio;

Variant a;

int mul2(Variant b){
int c = *b.peek!(int);
return 2*c;
}

int mul3(int b){
return 3*b;
}

void main()
{
a = 5;
writeln(mul2(a));

Variant b = 3;
writeln(mul3(*b.peek!int));
}

```
```On Friday, 9 October 2020 at 15:49:31 UTC, Ferhat Kurtulmuş wrote:
> On Friday, 9 October 2020 at 00:19:20 UTC, Marcone wrote:
>> How auto convert Variant to required function arguments?
>
>
> import std.variant;
> import std.stdio;
>
> Variant a;
>
> int mul2(Variant b){
>     int c = *b.peek!(int);
>     return 2*c;
> }
>
> int mul3(int b){
>     return 3*b;
> }
>
> void main()
> {
>     a = 5;
>     writeln(mul2(a));
>
>     Variant b = 3;
>     writeln(mul3(*b.peek!int));
> }
Uh, probably this is not what you want. I found this thread: https://forum.dlang.org/thread/ebylgcrslkelgrvntjws@forum.dlang.org

You man need to use Algebraic.

```
```On Friday, 9 October 2020 at 16:10:03 UTC, Ferhat Kurtulmuş wrote:
> On Friday, 9 October 2020 at 15:49:31 UTC, Ferhat Kurtulmuş wrote:
>> On Friday, 9 October 2020 at 00:19:20 UTC, Marcone wrote:
>>> How auto convert Variant to required function arguments?
>>
>>
>> import std.variant;
>> import std.stdio;
>>
>> Variant a;
>>
>> int mul2(Variant b){
>>     int c = *b.peek!(int);
>>     return 2*c;
>> }
>>
>> int mul3(int b){
>>     return 3*b;
>> }
>>
>> void main()
>> {
>>     a = 5;
>>     writeln(mul2(a));
>>
>>     Variant b = 3;
>>     writeln(mul3(*b.peek!int));
>> }
> Uh, probably this is not what you want. I found this thread: https://forum.dlang.org/thread/ebylgcrslkelgrvntjws@forum.dlang.org
>
> You man need to use Algebraic.

may*
```