Hi,
Is it OK?

-----
import std.stdio : writeln;
import std.range : takeNone;

void main() {

	auto s = takeNone("test");

	s ~= 5;

	writeln(s); // prints ♣
}
-----
Windows 8.1 x64, DMD 2.067.0

On Tuesday, 7 April 2015 at 02:24:00 UTC, Dennis Ritchie wrote:
> Is it OK?
Although, perhaps, everything is fine. I just thought that creates takeNone not string type string, and the string array of type string[].

import std.stdio : writeln;

void main() {

	string s;

	s ~= 5;

	writeln(s); // prints ♣
}

So I mixed up with this case. Everything is OK.

import std.range : takeNone;

void main() {
	
	auto s = takeNone(["test"]);
	
	// s ~= 5; // Error: cannot append type int to type string[]
}

Yes it is.

takeNone() take a char from a string.

So you are going to append a char (with code 5) on the next line.
If you replace that line with:

s ~= 65;

it will print "A".  (65 is ascii code for letter 'A')

On Tuesday, 7 April 2015 at 02:24:00 UTC, Dennis Ritchie wrote:
> Hi,
> Is it OK?
>
> -----
> import std.stdio : writeln;
> import std.range : takeNone;
>
> void main() {
>
> 	auto s = takeNone("test");
>
> 	s ~= 5;
>
> 	writeln(s); // prints ♣
> }
> -----
> Windows 8.1 x64, DMD 2.067.0

On Tuesday, 7 April 2015 at 08:49:58 UTC, Andrea Fontana wrote:
> Yes it is.
>
> takeNone() take a char from a string.
>
> So you are going to append a char (with code 5) on the next line.
> If you replace that line with:
>
> s ~= 65;
>
> it will print "A".  (65 is ascii code for letter 'A')

Thanks. I am aware :)