Hello, I am trying to write an integer to a file, but when I open the file it writes the char the number represents in ascii.

does anyone have a suggestion?

On Mon, 07 Mar 2011 11:26:25 -0000, yochi <yochib@gmail.com> wrote:
> Hello, I am trying to write an integer to a file, but when I open the
> file it writes the char the number represents in ascii.
>
> does anyone have a suggestion?

Post your code, people can then suggest changes.  Also, some things to consider:
 - Are you opening the file in ascii or binary mode?
 - Are you calling a function which writes an integer?

It sounds, from your description, that you're writing an integer 'as a char/byte' which probably means you've called the wrong function.

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this is part of the code:

void WritePushPop(cmd command, string segment, int index)
		{
                        string temp = "TextFile.Asm";
			AsmFile = new File(temp, FileMode.OutNew );

		        string x = toString(index);

AsmFile.writeString("@");

AsmFile.write(index);

AsmFile.writeLine("D=A");

AsmFile.writeLine("@0");

AsmFile.writeLine("A=M");

AsmFile.writeLine("M=D");

AsmFile.writeLine("D=A+1");

AsmFile.writeLine("@0");

AsmFile.writeLine("M=D");


}

Now it wouldn't even build, it doesn't like the line: string x =
toString(index);
but this line works when I'm working with the console.


Thanks!

On 07/03/2011 12:11, %u wrote:
> this is part of the code:

Posting the whole code (or even better, a minimal, complete program that shows the problem) helps a lot.

> void WritePushPop(cmd command, string segment, int index)
> 		{
>                          string temp = "TextFile.Asm";
> 			AsmFile = new File(temp, FileMode.OutNew );
>
> 		        string x = toString(index);
>
> AsmFile.writeString("@");
>
> AsmFile.write(index);

File.write writes a binary representation of its argument.  To write a textual representation, use writef or writefln.

<snip>
> Now it wouldn't even build, it doesn't like the line: string x =
> toString(index);
> but this line works when I'm working with the console.

What's the error message?

Stewart.